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\displaystyle \int \frac{2u}{u-1}\mathrm{d}u \\\\= 2\int \frac{u}{u-1}\mathrm{d}u \\\\= 2\int \frac{(u-1)+1}{u-1}\mathrm{d}u\\\\=2\int \left(\frac{u-1}{u-1}+\frac{1}{u-1}\right)\mathrm{d}u\]
\[\large \int \frac{2u}{u-1}du = 2\int \frac{u}{u-1}du = 2\int \frac{(u-1)+1}{u-1}du=2\int (\frac{u-1}{u-1}+\frac{1}{u-1})du\]
\display \sqrt{0.96} = \frac{\sqrt{24}}{\sqrt{25}} = \frac{2\sqrt{6}}{5}
\[\large \int \frac{2u}{u-1}du = 2\int \frac{u}{u-1}du = 2\int \frac{(u-1)+1}{u-1}du=2\int (\frac{u-1}{u-1}+\frac{1}{u-1})du\]