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can some differentiate 1/sin2x twice.

when 0 is subbed in the answer cant tend towards infinity. the answer should be secx^2tanx/4. I have no idea how to get to this point.
(sin2x)^-1 then you should know how to differentiate this.
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Avatar for crimson1234
crimson1234
OP
2
I've tried that. also tried equating it to cosec2x and solving along with multiple other methods. every answer i get still tends to infinity when 0 is subbed in.
You're still doing it wrong, sin2x should still be in a bracket at the end. There's only one way to differentiate it.
Reply 4
Avatar for crimson1234
crimson1234
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2
when i follow your method, this is what i get. which still gives me an answer that tends to infinity when 0 is subbed in since sin2x is in the denominatorimage (1).jpg
Reply 5
Avatar for TeeEm
TeeEm
19
what is the question exactly?
Reply 6
Avatar for crimson1234
crimson1234
OP
2
nvm my friend told me the wrong question. thanks for the help everyone

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