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Help with a Q needed

Can someone help with this q?
It's a little hard to read. Can you please take a clearer image closer in?
Reply 2
Original post by Vorsah
Can someone help with this q?


As above, preferably a screenshot!
Also please post what you've tried so far :smile:
Reply 4
I would imagine that if you integrate over the triangle you must get 1
Reply 5
Original post by TeeEm
I would imagine that if you integrate over the triangle you must get 1


Yh that's what I did and got C=1, but two of my friends got something else, which made me a little unsure.
Reply 6
Original post by Vorsah
Yh that's what I did and got C=1, but two of my friends got something else, which made me a little unsure.


post your workings please
Reply 7
Original post by TeeEm
post your workings please


Putting in (0,0) and (1,1) the function gives 0. Putting in (1,0) I get c*(1^6.98) =c

Then I integrated and got cx which must equal 1 then I put in the limits [0,1] and got c=1

Sorry if this doesn't look clear, but I'm on the train right now.
Reply 8
Original post by Vorsah
Putting in (0,0) and (1,1) the function gives 0. Putting in (1,0) I get c*(1^6.98) =c

Then I integrated and got cx which must equal 1 then I put in the limits [0,1] and got c=1

Sorry if this doesn't look clear, but I'm on the train right now.


I cannot check it right now either as I am in the middle of updating a website, but I will take a look when I finish.

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