The Student Room Group

Spectroscopy question chem4

ImageUploadedByStudent Room1455449502.546761.jpg

How would you answer this question?
Do u start by writing every fragmentation equation possible?


Posted from TSR Mobile
Reply 1
It isn't asking about fragmentation, the Q asks about the molecular ion peak/s.

Consider chloromethane. It will have two molecular ion peaks, one for CH335Cl and another due to CH337Cl.Now consider dichloromethane, there will be three peaks: one with 2x35Cl, two with 35Cl and 37Cl and one with 2x37Cl.

Your molecule has 4xCl atoms. You do the math.

Oooo 1500.
Original post by Pigster
It isn't asking about fragmentation, the Q asks about the molecular ion peak/s.

Consider chloromethane. It will have two molecular ion peaks, one for CH335Cl and another due to CH337Cl.Now consider dichloromethane, there will be three peaks: one with 2x35Cl, two with 35Cl and 37Cl and one with 2x37Cl.

Your molecule has 4xCl atoms. You do the math.

Oooo 1500.


Oh so there will be 5 peaks in total. Also what does the most abundant molecular ion mean


Posted from TSR Mobile
Reply 3
35Cl makes up about 75% of all the Cl atoms.

If you look at the MS of chloromethane, the peak at 50 (due to CH335Cl) is 3x the size of the peak at 52 (3:1 ratio = 75%:25%). The most abundant peak is simply the one that is most common, in that case, the peak at 50.

Of the five peaks, which is most common?
Original post by Pigster
35Cl makes up about 75% of all the Cl atoms.

If you look at the MS of chloromethane, the peak at 50 (due to CH335Cl) is 3x the size of the peak at 52 (3:1 ratio = 75%:25%). The most abundant peak is simply the one that is most common, in that case, the peak at 50.

Of the five peaks, which is most common?


Oh okay so I think I got it. The most abundant peak is at 224? Correct?


Posted from TSR Mobile
Reply 5
I make it 320.
Original post by Pigster
I make it 320.


Ah thanks I got it


Posted from TSR Mobile

Quick Reply

Latest