Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

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Help on calcus

Hey can someone tell me please for question iv why the area is 4 instead of -4 even though the Y-co ordinate is -2?

And can someone show me how to solve for x in this question:
2x^-1/2=3/2x^1/2

Original post by Msjaygaab

Hey can someone tell me please for question iv why the area is 4 instead of -4 even though the Y-co ordinate is -2?

And can someone show me how to solve for x in this question:
2x^-1/2=3/2x^1/2

Well, you can't have negative area, can you? :h:

:h:

For the second part, why don't you try multiplying both sides by sqrt(x)?

OP

Oh yeah Thankyou
And could you please show me how to do the second part im still unsure

Do you mean part b?

Posted from TSR Mobile

Original post by Msjaygaab

And can someone show me how to solve for x in this question:
2x^-1/2=3/2x^1/2

\displaystyle \frac{2}{\sqrt{x}} = \frac{3\sqrt{x}}{2} \Rightarrow 2 = \frac{3x}{2} \Rightarrow \cdots

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