Thanks.
I searched online for how to obtain the horizontal and vertical asymptotes. However, I have never learnt this so I might be wrong.
Therefore, I am assuming for part (a) I have to find the asymptotes of y=f(x) and then just find the transformation right?
If so, I did this to get the VA:
x-1=0 Hence x=1, which is why x will never equal 1
So y=f(x-3) means x=1 becomes x=1+3 which is x=4
And for the HA:
Using 1x^1/(1x^1-1), the highest powers are equal so I use the leading coefficients 1/1=1
Then, since y=f(x-3) will not affect the y values as it is in the brackets, y=1 will remain as y=1
In part (b) I made y=f(x) equal to y=f(x-3)So x/(x-1)=(x+3)/(x-1+3)
Eventually, I got 0=-3 but since that is impossible I thought no solutions meant there are no points of intersections.
Now, did I get this question right, partially right or was I completely wrong?