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Advanced Higher Maths Help

Anyone able to help me with this parametric equation?

d^2y/dx^2 = t^2 +1

dy/dx = t^3 + 2t

Find x(t) given that x(1) = 4





I've started off by doing the simple dy/dx = (dy/dt) / (dt/dx) and d^2y/dx^2 = d/dt(dy/dx) x dt(dx), I just don't have a clue what to do after it. Thanks in advance.
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Reply 2
Avatar for gwagon
gwagon
18
d^2y/dx^2 = d/dx(dy/dx)/(dx/dt)
Differentiate dy/dx and substitute the values for d^2y/dx^2 and d/dx(dy/dx).
rearrange for dx/dt.
Integrate dx/dt to find x(t). Use x(1) = 4 to find the constant from integration.
Reply 3
Avatar for Yammy
Yammy
15
I need help too...
http://www.millburnacademy.co.uk/wp-content/uploads/2012/06/AH-2002.pdf
What is A10 even asking? It looks like a sequence question to me? Why is Sn(1) not 1+2+3+...+n(1)^(n-1)?

Thanks

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