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Titration Question, I'm Really Really Last Minute Stuck!!! I Know, how juicy

Ok, so you're doing an enthalpy of neutralisation test.

and all's well

you got your graph, worked out q=mc T

But then the mark scheme says "scales up to molar quantities"

and you're thinking wtf?!?!

in the mark scheme it says e.g. x40 for 25cm3 , but I dont know what they mean by this


anyone help a dumb lil chemist? :redface:
Reply 1
Molar quantity is another way of saying molar concentration. However without the question it is difficult to say where the 40 comes from. Could you possibly post the question?
Reply 2
Enthalpy of Neutralisation question: Monoprotic acid reacting with NaOH

the scale of working used
sensible volume of HA solution ( 20 cm3 to 100 cm3)
sensible volume of NaOH solution ( same or slight excess )
appreciates need for significant ΔT ( at least 5 deg )
appropriate concentration of HA solution ( at least M )

"To score last two points need a definite correct link between conc and ΔT"

... what's the link?
This is the question

When a monobasic acid, HA, in aqueous solution is neutralised by a solution of sodium hydroxide,
the following exothermic reaction occurs.

HA(aq) + NaOH(aq) → NaA(aq) + H2O(l)

When equal volumes of a 0.2 mol dm–3 solution of HA and a 0.2 mol dm–3 solution of sodium hydroxide react together, the temperature rises by about 1°C.


3. A clear explanation, including a sketch graph of temperature against time, showing how you would use your results to calculate, in kJ mol–1, the enthalpy change of neutralisation of the unknown acid, HA.

:confused: :s-smilie:
Reply 4
I think what they mean is that after you work out your ∆H you should divide that by the moles of acid.
Excalibur
I think what they mean is that after you work out your ∆H you should divide that by the moles of acid.


hmmm maybe but in the mark scheme it says e.g. x40 for 25cm3
Reply 6
bubble_gum_pop
Ok, so you're doing an enthalpy of neutralisation test.

and all's well

you got your graph, worked out q=mc T

But then the mark scheme says "scales up to molar quantities"

and you're thinking wtf?!?!

in the mark scheme it says e.g. x40 for 25cm3 , but I dont know what they mean by this


anyone help a dumb lil chemist? :redface:


I have absolutely no idea why. I can see that 40 * 25cm3 = 1000 cm3 i.e. 1 dm3

Thus you'd have 1M of whatever the solution is, which is useful apparently if that's the concentration you chose to use.
booraad
I have absolutely no idea why. I can see that 40 * 25cm3 = 1000 cm3 i.e. 1 dm3

Thus you'd have 1M of whatever the solution is, which is useful apparently if that's the concentration you chose to use.


oooohhhhhh....c uve answered ur own question

thanks a million...my exams in an hour! :smile:
Reply 8
Hi... I have no idea WHY it's useful to scale up.. but if that's what they want.

I have the exam this afternoon!

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