Urgently need help! - homogeneous equilibrium calculations involving Kc
Please can somebody help me with this and please can you explain your answer as well
How many moles of ethanol must be mixed with 3 mol of ethanoic acid at 373 K to produce 2 mol of ethyl ethanoate? (At this temperature, Kc, for the reaction CH3COOH + C2H5OH (reversible reaction sign) CH3COOC2H5 + H2O = 4.0)
How many moles of ethanol must be mixed with 3 mol of ethanoic acid at 373 K to produce 2 mol of ethyl ethanoate? (At this temperature, Kc, for the reaction CH3COOH + C2H5OH (reversible reaction sign) CH3COOC2H5 + H2O = 4.0)
Original post by Pigster
3
Do an ICE table.
I happened to start with 3 mol of EtOH and it turned out to be the right answer.
Do an ICE table.
I happened to start with 3 mol of EtOH and it turned out to be the right answer.
Thank you!
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