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M1 question on moments

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for 6c)of this question,how do you work out k? Please give simple explanation only as it will confuse me even more. Thanks
Reply 1
Try to provide what you have attempted. There is a weight where the string at b is under zero tension. This is the maximum value of k. Any k lower than this will mean that both strings are taking some weight rather than the rod pivoting about c.
Reply 2
Original post by nerak99
Try to provide what you have attempted. There is a weight where the string at b is under zero tension. This is the maximum value of k. Any k lower than this will mean that both strings are taking some weight rather than the rod pivoting about c.


HI, this is what I did. Please could you show me a diagram for the explanation? Thanks.1456831198549-1268971868.jpg
Reply 3
img002.jpg
Your diagram is fine although I would have neglected using 'N' in the labels as I think that the N confuses things as it looks like a variable.

My calculation is different though 23W=2Rb+kW        T=W2(23k)\frac{2}{3}W=2R_b + kW \;\;\Rightarrow\;\; T=\frac{W}{2}\left(\frac{2}{3}-k \right) You have put kW i the wrong direction (as you are equating CW and ACW moments, the moment at D is CW).

Once you have done this we can see that RbR_b is zero when
k=23k=\frac{2}{3}
(edited 8 years ago)

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