You are Here: Home >< Maths

# AQA A2 MFP3 Further Pure 3 – 18th May 2016 [Exam Discussion Thread]

Announcements Posted on
TSR's new app is coming! Sign up here to try it first >> 17-10-2016
1. (Original post by JDMason)
1. Ae^5x/2 - 2x - 4/5

2. 5/3, 8/5

3. Approximation: 2.081, 2.080

4. c=36, d=20, traslate 4 across

5. 0.5x^2 +3x +ln(x+1) +1

6. 1/36

7. I got my constants wrong but I believe this is correct: y= 2cos2x - 1/2(e^pi)sin2x + 1/2(e^4x) + xSin2x - 2xcos2x

8. (1/2)ln3 - 1/2

roast me
Got all the same answers except for p and q, but I think I got that wrong. I think you should post this as unofficial ms. 😃
2. I noticed that AQA have completely changed the design of the front cover of the paper, dk why.
3. (Original post by IrrationalRoot)
I noticed that AQA have completely changed the design of the front cover of the paper, dk why.
They're changing everything because they ****ing hate us.
4. The unnoficial answers posted seem all correct, I will append them to the first post later
I made some silly errors but nothing content wise, just arithmetic slips :/

Posted from TSR Mobile
5. For the very last question, the area one:

Was the asnwer the integral of (1+tanX) between pi/3 and the value of theta at B, minus the area of the triangle (3+2√3)/6
??

Posted from TSR Mobile
6. I got something along the lines of y= 0.5x^2 +3x -ln(X+1) +cx -(2+C)ln(X+1) +2cln(X+1) + B is this along the right lines, I had noticed a similar answer on the thread but without the two constants? Were there constraints that I failed to spot?
7. (Original post by Barbecuetime123)
I got something along the lines of y= 0.5x^2 +3x -ln(X+1) +cx -(2+C)ln(X+1) +2cln(X+1) + B is this along the right lines, I had noticed a similar answer on the thread but without the two constants? Were there constraints that I failed to spot?
8. What was question number 5?
For the very last question, the area one:

Was the asnwer the integral of (1+tanX) between pi/3 and the value of theta at B, minus the area of the triangle (3+2√3)/6
??

Posted from TSR Mobile
This is what I did, got something like .5ln(3) -.5
For the very last question, the area one:

Was the asnwer the integral of (1+tanX) between pi/3 and the value of theta at B, minus the area of the triangle (3+2√3)/6
??

Posted from TSR Mobile
(1+tanX)^2 mate, you gotta square it in polar. also half it

but otherwise I think so yeah
11. (Original post by Xzielon)
5 I think, where u = y' abd you had to make a subs.
12. (Original post by Barbecuetime123)
5 I think, where u = y' abd you had to make a subs.
I didn't know what to do there either. I differentiated u and tried plugging in the partial fractions but that's as far as I went.
13. (Original post by Xzielon)
I didn't know what to do there either. I differentiated u and tried plugging in the partial fractions but that's as far as I went.
Once I made the substitution, I used an integrating factor and then integrated both sides as normal for u, then integrated to get y. Not sure why my answer was so messed up, I had to do a bit of nasty manipulating to be able to integrate too.
14. (Original post by Barbecuetime123)
Once I made the substitution, I used an integrating factor and then integrated both sides as normal for u, then differentiated to get y. Not sure why my answer was so messed up, I had to do a bit of nasty manipulating to be able to integrate too.
I wanted to use the integrating factor but I wasn't sure if I should. I thought that's a way to go but it would make it messy so I kept thinking about an easier way and time run out as I wanted to try it for the sake of it.
15. (Original post by Xzielon)
I didn't know what to do there either. I differentiated u and tried plugging in the partial fractions but that's as far as I went.
basically what I did:

sub in u and du/dx for dy/dx and d2y/dx2

get integrating factor using partial fractions integral (I got the reciprocal of the RHS bit)

integrate 1 and solve how you would an integrating factor one

sub u back out so you get dy/dx = a load of crap

then you have some horrible shite to integrate and you had to rewrite it as x+3+1/(x+1) I think it was, something like that

then you have equation, sub in 0 to find constant value

I got what everyone else got, y = x^2/2 + 3x + ln(x+1) +1
16. Let's just hope the grade boundaries are like, 20 marks for an A :'(
Flopped too hard, I got all positives for question 1, question 2 can't remember, done half of question 4 and flopped 6. Missed out the 4 marker for question 8 :'(
17. (Original post by Mop3476)
basically what I did:

sub in u and du/dx for dy/dx and d2y/dx2

get integrating factor using partial fractions integral (I got the reciprocal of the RHS bit)

integrate 1 and solve how you would an integrating factor one

sub u back out so you get dy/dx = a load of crap

then you have some horrible shite to integrate and you had to rewrite it as x+3+1/(x+1) I think it was, something like that

then you have equation, sub in 0 to find constant value

I got what everyone else got, y = x^2/2 + 3x + ln(x+1) +1
Can you remember the original equation? I wanna try what I planned to do
For the very last question, the area one:

Was the asnwer the integral of (1+tanX) between pi/3 and the value of theta at B, minus the area of the triangle (3+2√3)/6
??

Posted from TSR Mobile
what value of theta at b did you get?
19. (Original post by IrrationalRoot)
I noticed that AQA have completely changed the design of the front cover of the paper, dk why.
That **** didn't even tell us how many Qs there were...
20. anyone know the allocation of marks for all parts of the questions if i remember right it was something like
1a. 3
b. 3

2a. 1
b. 4

3a. 6
b. 3
c. 3
ci. 1

4. 5

5a. 1
b. 11

6a. 3
b. 4

7. 10

8a. 3
b. 4
c. 3
d. 7

## Register

Thanks for posting! You just need to create an account in order to submit the post
1. this can't be left blank
2. this can't be left blank
3. this can't be left blank

6 characters or longer with both numbers and letters is safer

4. this can't be left empty
1. Oops, you need to agree to our Ts&Cs to register

Updated: August 17, 2016
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Today on TSR

### How does exam reform affect you?

From GCSE to A level, it's all changing

Poll
Useful resources