Hi everyone,
We have just done a tritation calculation for an equilibrium reaction. This involved an acid catalyst, mixed with ethanol and ethanoic acid.
I know the number of moles of the catalyst, and the number of moles of NaOH which reacted with the catalyst and any remaining ethanoic acid, but how I calculate tye number of moles of ethanoic acid which reacted with the alcohol?
Mol. Of HCl = 0.015
Mol. Of NaOH = 0.003725