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# Unit 4 Physics - SHM Question

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1. Here are the links to the question:
Part 1: http://prntscr.com/amtyqc
Part 2: http://prntscr.com/amtz1j

I've worked out part one by just doing the following calculation to work out the time period, time/no. of oscillations, this had given me a value of :
2.8 Seconds

Right, now the second part I was confused by; it is asking us to calculate the kinetic energy as she passed through the lowest point, at this point velocity is max and displacement is zero right? So I calculated Vmax with 2*Pi*f*A, which had given me 0.56 m/s and plugged this value into Ek = 1/2*m*v^2 which then had given me 2.83J. However this was incorrect as the mark scheme stated to work out the kinetic energy all that was required was to equate mgh=1/2*m*v^2, where 'h' in this case was the given amplitude, I just don't understand why my approach was incorrect.
2. Sorry you've not had any responses about this. Are you sure you've posted in the right place? Here's a link to our subject forum which should help get you more responses if you post there.

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Just quoting in Puddles the Monkey so she can move the thread if needed
Spoiler:
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(Original post by Puddles the Monkey)
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