You are Here: Home >< Maths

# Maths Question?

Announcements Posted on
TSR's new app is coming! Sign up here to try it first >> 17-10-2016
1. (Original post by Dinaa)
I think OP is talking about the change in y would be 0 and the change in x= a constant

therefore change in y/change in x= constant/0
Is that meant to be in that order? (you said change in y=0, but then in the equation put it as a constant?)

I actually meant that if x=3, then y values are changing but x aren't, and thus dy/dx is a constant divided by 0.

But don't worry now, I understand!
2. (Original post by mil88)
Is that meant to be in that order? (you said change in y=0, but then in the equation put it as a constant?)

I actually meant that if x=3, then y values are changing but x aren't, and thus dy/dx is a constant divided by 0.

But don't worry now, I understand!
oops I need to stop with the typos

## Register

Thanks for posting! You just need to create an account in order to submit the post
1. this can't be left blank
2. this can't be left blank
3. this can't be left blank

6 characters or longer with both numbers and letters is safer

4. this can't be left empty
1. Oops, you need to agree to our Ts&Cs to register

Updated: April 3, 2016
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Today on TSR

### How does exam reform affect you?

From GCSE to A level, it's all changing

Poll
Useful resources

### Maths Forum posting guidelines

Not sure where to post? Read here first

### How to use LaTex

Writing equations the easy way

### Study habits of A* students

Top tips from students who have already aced their exams