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# OCR (non mei) M1 Friday 17th June 2016

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Why bother with a post grad course - waste of time? 17-10-2016
1. (Original post by daniellon)
Cosine rule in the formula booklet?
Yep
2. What was the tension before P was released?
3. (Original post by daniellon)
What was the tension before P was released?
O.2g = 1.96?
Distance: 10, time 1.43
a=6.8
3, 1.25
82.7
82.8
0.918, 48.6
6
3.75
4.75
12, 16.3
2.06 (east)
1.96, 1.81
3.64
1.96?
10
3, 25 (as shown)
6.76
5. (Original post by Furthermaths100)
Distance: 10, time 1.43
a=6.8
3, 1.25
82.7
82.8
0.918, 48.6
6
3.75
4.75
12, 16.3
2.06 (east)
1.96, 1.81
3.64
1.96?
10
3, 25 (as shown)
6.76
Please could you help by putting these into the community MS?
6. (Original post by Furthermaths100)
Distance: 10, time 1.43
a=6.8
3, 1.25
82.7
82.8
0.918, 48.6
6
3.75
4.75
12, 16.3
2.06 (east)
1.96, 1.81
3.64
1.96?
10
3, 25 (as shown)
6.76
I got 2.37 instead of 1.96
7. (Original post by Parallex)
Ahh, fair enough. Looks like I pictured the resultant force wrongly...
8. (Original post by Parallex)
your cosine rule is wrong. it's a^2 + b^2 - c^2 not (a^2 - b^2 - c^2)
9. (Original post by physicskid123)
your cosine rule is wrong. it's a^2 + b^2 - c^2 not (a^2 - b^2 - c^2)
It isn't wrong..
10. (Original post by Parallex)
It isn't wrong..
it is
11. For question 5 I said the direction is to the right. Can I get away with it
12. your cosine rule is wrong. it's a^2 + b^2 - c^2 not (a^2 - b^2 - c^2)

- You're a moron.
14. What are people predicting for grade boundaries?
15. look it's cos a = (4^2 + 4^2 - 6^2) / 2*4*4 so cos a = -.125 and so a is 97.18
16. (Original post by Parallex)
That equation isn't correct.

You did b^2 + c^2 - a^2/ -2bc but there shouldn't be a minus
It should be just 2bc
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17. (Original post by daniellon)
For question 5 I said the direction is to the right. Can I get away with it
I did too
18. What was the total mark for the question with the 2 4N forces because I got that whole bit wrong
19. Just a quick question for question 4 part iii. In the unofficial mark scheme it mentioned that it had already been verified. However in the question it said that after B collides with CD that there are no more collisions after this point. This means that surely B can not have a velocity of zero as A would then collide with B. Therefore shouldn't the velocity of B be at least greater than 4ms^-1 (which was the previous speed of A).

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