You are Here: Home >< Physics

Calculating tension (materials)

Announcements Posted on
Would YOU be put off a uni with a high crime rate? First 50 to have their say get a £5 Amazon voucher! 27-10-2016
1. An elastic cord of unstretched length 160mm has a cross sectional area of 0.64m^2. The cord is stretched to a length of 190mm. Assume that Hooke's law is obeyed for this range and that the cross sectional area remains constant.
The young modulus for the material of the cord = 2.0*10^7 Pa.

Calculate the tension in the cord at this extension.

I'm confused about what formulae I am meant to be using/how to apply them. I tried to do something by working out the stress and the strain, but I don't know how to get the answer.
Guidance is appreciated
2. Stress = Tension / Cross sectional area

Youngs modulous = stress / strain

You can find the strain by subtracting the extended length from the original length divided by the original length.

You already have the Youngs modulous, the cross sectional area and the lengths.

Very simple tbh.

Register

Thanks for posting! You just need to create an account in order to submit the post
1. this can't be left blank
2. this can't be left blank
3. this can't be left blank

6 characters or longer with both numbers and letters is safer

4. this can't be left empty
1. Oops, you need to agree to our Ts&Cs to register

Updated: April 11, 2016
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Today on TSR

University open days

Is it worth going? Find out here