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# [Official Thread] OCR MEI AS Mathematics 2016 (C1, C2 & S1)

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1. (Original post by Jowen12)
1.8 I believe? Probably wrong though!
I'm not 100% sure but I think it was 0.8
2. (Original post by Studious_Student)
What was the value of theta for the sector question again? I remember somewhat that the radius was 12
It was 0.8
3. (Original post by Jowen12)
1.8 I believe? Probably wrong though!
It was 0.8
4. Thank you!
(Original post by Mr Moon Man)
Sin(X)=0 for 0,180, and 360
5. (Original post by ineedA)
Sup, did exactly the same, you and I both integrated the value before the brackets right? You're not meant to do that, if you carried on and multiplied it by 50 then we'll probably get W for method marks
Not supposed to integrate 8/51 or whatever it was? How come?
6. (Original post by WuMyster)
Not supposed to integrate 8/51 or whatever it was? How come?
5/81

When integrating, a constant value which applies to the whole integral can be put outside of the integral before integrating
7. (Original post by tizzaclaire98)
5/81

When integrating, a constant value which applies to the whole integral can be put outside of the integral before integrating
Oh crap I remember learning that but that didn't come up in any of my textbooks (retaker). Oh well.
8. With the sin graph translation did you guys move it 3 units down. There were no brackets so I was unsure?
9. (Original post by WuMyster)
Oh crap I remember learning that but that didn't come up in any of my textbooks (retaker). Oh well.
It actually comes up much more in C3 - surprised it was put into C2
10. (Original post by mp1998)
With the sin graph translation did you guys move it 3 units down. There were no brackets so I was unsure?
Yeah it was strange without brackets. I believe it was translating 3 units down though
11. (Original post by tizzaclaire98)
It was 0.8
Ah okay my mistake!
12. guys for that question with "f(h+5) - f(5)/h" could you assume that h represents the the change in x and so when when x=5 the change in x would be 0 and so u sub that into the simplified "h+8" to geit "0+8" which gives you 8, the answer???? or am i way off
13. (Original post by Jowen12)
1.8 I believe? Probably wrong though!
it was 0.8
14. So then wouldn't the answer be a = 12.7? Because the unofficial markscheme says a = 8.96

r^2/2 x Theta = a^2/2 x sin(theta)

Sub values in:

144/2 x 0.8 = a^2/2 x Sin (0.8)

(288/5)/sin (0.8) = a^2/2 ---> 80.2948504 = a^2/2

160.5897008 = a^2

a = 12.67 = 12.7 (3 sig figs) ?
15. (Original post by tizzaclaire98)
Its a differentiation by first principles question.

Q:
y = x^2 - 2x
find dy/dx on the chord between x=5 and x=5.1.

A:
8.1

Q:
given that f(x) = x^2 - 2x
find (f(5+h) - f(5))/h

A:
sub 5+h for x:
(5+h)^2 - 2(5+h) = 25+10h+h^2 -10 -2h = 15 +8h +h^2
minus f(x) sub 5 for x:
15+8h+h^2 - (25-10)= 8h+h^2
Divide by h:
8 + h

Q:

A:
deltay/deltax = 8 + h
as h tends to 0, gradient tends to 8, so dy/dx = 8
I left it as 8h+8h^2
At first I couldn't see why you did that then I saw it was in the original equation, made so many stupid mistakes like this!
Will I just lose 1 mark?
16. (Original post by ant1greeny)
I left it as 8h+8h^2
At first I couldn't see why you did that then I saw it was in the original equation, made so many stupid mistakes like this!
Will I just lose 1 mark?
I imagine so - no more than 2 I would think
17. (Original post by tizzaclaire98)
Attachment 545879

Can someone explain why I only got two values? thanks
You're not meant to divide by sinx. You had to bring it all over to one side and then take the brackets so
Sinx(4sinx-1)=0
Sinx=0 and Sinx=1/4
18. (Original post by tizzaclaire98)
It actually comes up much more in C3 - surprised it was put into C2
Come to think of it, I think I remember learning that from C3 and not in C2. Weird.
19. Does anyone have a picture of the paper? Or at least the first few? I wanna see the wording of the sequences question for question 2... Threw me off a bit
20. (Original post by Lucuniexet)
for the simplifying log question i got -3m
is this familiar to anyone?!
I got this! Because I had -logaA^3m which simplified to -3mlogaA which gives -3m, right?

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