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# Questions on Logs

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1. The question is
Lnx/x^2 = 0

I need to solve it but for some reason the answer is 1, but I dont get how its one, because if i take the x to the power of 2 to the other side, and E both sides you get

X = e to the power of x^2
2. , so we are looking for to = 1.
3. (Original post by SunDun111)
The question is
Lnx/x^2 = 0

I need to solve it but for some reason the answer is 1, but I dont get how its one, because if i take the x to the power of 2 to the other side, and E both sides you get

X = e to the power of x^2
If you take the to the other side, do you not get ?
4. (Original post by rayquaza17)
If you take the to the other side, do you not get ?
Oh yeah, that works out thanks
5. (Original post by SunDun111)
The question is
Lnx/x^2 = 0

I need to solve it but for some reason the answer is 1, but I dont get how its one, because if i take the x to the power of 2 to the other side, and E both sides you get

X = e to the power of x^2
if a/b = 0 then a = 0
6. I think some of the above didn't realise you meant:

(ln x) / (x2) = 0
I think some of the above didn't realise you meant:

(ln x) / (x2) = 0
Yeah i did but isnt what they said still true?
8. (Original post by SunDun111)
Yeah i did but isnt what they said still true?
(Original post by rayquaza17)
If you take the to the other side, do you not get ?
This one is correct^ yes. Did you manage to see how the answer was reached after following this?
This one is correct^ yes. Did you manage to see how the answer was reached after following this?
yeah taking E to both sides got me X = 1, is the rule a/b=0 means a=0 valid for everything
10. (Original post by SunDun111)
yeah taking E to both sides got me X = 1, is the rule a/b=0 means a=0 valid for everything
assuming b is non-zero, yes.
11. (Original post by SunDun111)
yeah taking E to both sides got me X = 1, is the rule a/b=0 means a=0 valid for everything
Yep what you'll see with a slightly more complex equations is you can use that rule to help:

e.g. (x2+3) / (3-y3) = 0

This means you can just get rid of the bottom and solve for x. I know this different to your question, but that's basically to show that it works.

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