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# Trig parametric differentiation problem C4

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1. Hi there, I can't do any of the trig problems on question 9. Urgent help and/or solutions needed!
2. (Original post by TheKevinFang)
Hi there, I can't do any of the trig problems on question 9. Urgent help and/or solutions needed!
Urgent thoughts and/or workings needed!
3. .
4. (Original post by TheKevinFang)
Hi there, I can't do any of the trig problems on question 9. Urgent help and/or solutions needed!
I'll do an example for you. For the first part of Q9, since x=t, dx/dt = 1, so dt/dx=1/1 = 1, and since y=t^2, dy/dt = 2t.
Thus by the Chain Rule, dy/dx = dy/dt * dt/dx = 2t * 1 = 2t, so when t = -1, dy/dx = -2.
Also you can calculate that since t = -1, x = -1 and y = 1.
Thus the equation of the tangent is y-1=-2(x-(-1)) -> y-1=-2(x+1) = -2x-2 -> y=-2x-1.

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