You are Here: Home >< Physics

# Unit 4 Physics Edexcel A2 and Edexcel IAL

Announcements Posted on
Would YOU be put off a uni with a high crime rate? First 50 to have their say get a £5 Amazon voucher! 27-10-2016
1. [QUOTE=PhysicsIP2016;65820117]
Q5 on June 2013 R

Posted from TSR Mobile
Could any help in explaining why the answer is B. Why is charging instantaneous when switch is closed?
Attached Images

2. [QUOTE=ayvaak;65824885]
(Original post by PhysicsIP2016)

Posted from TSR Mobile
Could any help in explaining why the answer is B. Why is charging instantaneous when switch is closed?
When the switch is closed the capacitor charges up. However, as the capacitor doesn't charge through the resistor there is no resistance when charging. Therefore t = RC = 0, which means the capacitor will charge up instantaneously.
3. [QUOTE=Mowerharvey;65825199]
(Original post by ayvaak)

When the switch is closed the capacitor charges up. However, as the capacitor doesn't charge through the resistor there is no resistance when charging. Therefore t = RC = 0, which means the capacitor will charge up instantaneously.
Thank thay was really useful to clear that up.

Could anyone help me with this question. Im not sure where why the frequencies have to be compared?

Posted from TSR Mobile
Attached Images

4. Posted from TSR Mobile[/QUOTE]

Why is initial momentum

Posted from TSR Mobile

Also guys. Im not sure how you can simply take the momentums above theta zero from those below the zero to find the muons momentum. Also is the vector diagram that i drew correct. Thanks in advance
Attached Images

5. Im probably being stupid but i cant work out why the answer to the question is C and not D

Posted from TSR Mobile
Attached Images

6. (Original post by ayvaak)
Im probably being stupid but i cant work out why the answer to the question is C and not D

Posted from TSR Mobile
An alpha particle has a charge of +2 and a beta particle has a charge of -1. Therefore the alpha particle has 2q in the equation.
7. I cant quite understand where im going wrong with part bii) any help would be greatly appreciated
8. (Original post by ayvaak)
I cant quite understand where im going wrong with part bii) any help would be greatly appreciated
Why is the answer B? Im struggling to work out why

Posted from TSR Mobile
Attached Images

9. (Original post by ayvaak)
Why is the answer B? Im struggling to work out why

Posted from TSR Mobile
The charge on an alpha particle is 2+ so you have F of alpha=2Bqv and F of beta=15Bqv so then you divide one by other to get the ratio. Hope that helps.
10. Thank you. That makes sense now

Posted from TSR Mobile
11. (Original post by Mowerharvey)
An alpha particle has a charge of +2 and a beta particle has a charge of -1. Therefore the alpha particle has 2q in the equation.
Thank you

Posted from TSR Mobile
12. Could anyone explain the theory behind the answer in the MS in a little more detail for this question?

Thanks
Attached Images

13. Could anyone help me with derivation from s
SI units?
Attached Images

14. And also in deriving this? Im not quite sure why the answers B? I keep getting D for some reason
Attached Images

15. (Original post by ayvaak)
Could anyone help me with derivation from s
SI units?
F=BIL
in units: N = T x Amps x m (length)
therefore T = N / (A x m)

Hope it helps!
16. (Original post by ayvaak)
And also in deriving this? Im not quite sure why the answers B? I keep getting D for some reason
Hi. You have the graph of Force and time so the area under the graph represents the momentum. As you get momentum, they have asked to find the speed so you have the mass and momentum also(as you calculated it). Now simply, just substitute the values in the formula for Momentum= Mass multiplied by Velocity and you will get your answer
17. (Original post by ayvaak)
And also in deriving this? Im not quite sure why the answers B? I keep getting D for some reason
Area under the graph represents change in momentum, i.e. m(v-u) but since he starts from rest, u = 0. Therefore area under graph = mv

area = 8x5x0.5 = 20
20 = mv
20 = 1.5v
v= 13.3333
18. Can someone help me with Q13? I don't even understand what this is asking.. Thanks!

https://60abffc9b401b1c0936e01291c15...%20Physics.pdf
19. (Original post by pinksmartiee)
Area under the graph represents change in momentum, i.e. m(v-u) but since he starts from rest, u = 0. Therefore area under graph = mv

area = 8x5x0.5 = 20
20 = mv
20 = 1.5v
v= 13.3333
(Original post by sabahshahed294)
Hi. You have the graph of Force and time so the area under the graph represents the momentum. As you get momentum, they have asked to find the speed so you have the mass and momentum also(as you calculated it). Now simply, just substitute the values in the formula for Momentum= Mass multiplied by Velocity and you will get your answer
(Original post by pinksmartiee)
F=BIL
in units: N = T x Amps x m (length)
therefore T = N / (A x m)

Hope it helps!
Thanks so much guys

Posted from TSR Mobile
20. Also.. Q15)a)iii) and
Q16b)ii) I don't know where the markscheme got p = E/c from..

http://qualifications.pearson.com/co...e_20110127.pdf

## Register

Thanks for posting! You just need to create an account in order to submit the post
1. this can't be left blank
2. this can't be left blank
3. this can't be left blank

6 characters or longer with both numbers and letters is safer

4. this can't be left empty
1. Oops, you need to agree to our Ts&Cs to register

Updated: June 21, 2016
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Today on TSR

Find out here

Poll
Useful resources