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# P(-1.34<z<1.60)

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1. P(-1.34<Z<1.60) = P(Z<1.60) - P(Z>-1.34)

P(Z<1.60) - ....

How do I finish it off I understand that it is

P(Z<1.60) - (1-P(Z<1.34))

Could someone explain how to do the rearranging please.
2. (Original post by L'Evil Wolf)
P(-1.34<Z<1.60) = P(Z<1.60) - P(Z>-1.34)

P(Z<1.60) - ....

How do I finish it off I understand that it is

P(Z<1.60) - (1-P(Z<1.34))

Could someone explain how to do the rearranging please.
As in:

P(Z<1.60) +P(Z<1.34) -1?
3. (Original post by Slowbro93)
As in:

P(Z<1.60) +P(Z<1.34) -1?
Yes it is that, but I dont know how to proceed from this point:

P(-1.34<Z<1.60) = P(Z<1.60) - P(Z>-1.34)

I would like to understand that maths rearranging of it
4. (Original post by L'Evil Wolf)
Yes it is that, but I dont know how to proceed from this point:

P(-1.34<Z<1.60) = P(Z<1.60) - P(Z>-1.34)

I would like to understand that maths rearranging of it
Gonna draw it, give me two secs
5. (Original post by Slowbro93)
Gonna draw it, give me two secs
thanks b0ss

6. I've basically drawn the whole process out, does this help

(Original post by L'Evil Wolf)
thanks b0ss
7. (Original post by Slowbro93)

I've basically drawn the whole process out, does this help
omg I was messing up the symmetry part, thank you.

I will definitely draw out until I get more acquainted. Thanks for the time taken to upload etc.
8. (Original post by L'Evil Wolf)
omg I was messing up the symmetry part, thank you.

I will definitely draw out until I get more acquainted. Thanks for the time taken to upload etc.
No worries I've always found diagrams a really nice way to represent certain concepts and given during my PhD I still use them
9. (Original post by L'Evil Wolf)

I will definitely draw out until I get more acquainted. Thanks for the time taken to upload etc.
Keep drawing them even if you are acquainted.
10. (Original post by Zacken)
Keep drawing them even if you are acquainted.
great tip yeah, for S3 the graphical calc can do it but for stuff like STEP probably not :P
11. (Original post by L'Evil Wolf)
great tip yeah, for S3 the graphical calc can do it but for stuff like STEP probably not :P
Ew. No, don't use a graph calc. Use pen and paper.
12. (Original post by Zacken)
Ew. No, don't use a graph calc. Use pen and paper.
Can you explain page 9. Q6.

By the same principle I get 0.8185 which is wrong it should be 1-ans.

Is it different to the other quesiton?
13. (Original post by L'Evil Wolf)
Can you explain page 9. Q6.

By the same principle I get 0.8185 which is wrong it should be 1-ans.

Is it different to the other quesiton?
What question are you talking about? Page 9, Q6 what?
14. (Original post by Zacken)
What question are you talking about? Page 9, Q6 what?
https://771a1ec81340d97ae9ed29694f73...XZCVmc/CH1.pdf

Sorry
15. This is different because both P(something < blah) has blah being positive. In your previous question on this thread, you had blah being negative. So basically just do what the solution bank did. Sketch the normal graph, sketch the bit for X-Y < 16, and then < 13. Then you'll see why you need to subtract the two if you want just the bit inbetween them.
16. (Original post by Zacken)
This is different because both P(something < blah) has blah being positive. In your previous question on this thread, you had blah being negative. So basically just do what the solution bank did. Sketch the normal graph, sketch the bit for X-Y < 16, and then < 13. Then you'll see why you need to subtract the two if you want just the bit inbetween them.
Thank you this makes a lot of sense.
17. (Original post by L'Evil Wolf)
Thank you this makes a lot of sense.
No problem.

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