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Have I done this correctly?

http://prntscr.com/az6jmc

Have I done this correctly? If not what have I done wrong thanks.
Reply 1
Original post by junayd1998
http://prntscr.com/az6jmc

Have I done this correctly? If not what have I done wrong thanks.


Unfortunately not! :no: You've found the area contained within the square but outside the circle, but that isn't the shaded area.

Instead, think about it like this:

The shaded area is the area of the square (6 * 6) minus the area of the quarter circle.
Reply 2
There's the solution. I don't believe you'd have to factorise it at the end, leaving it as it is would be fine.
Reply 3
Original post by Zacken
Unfortunately not! :no: You've found the area contained within the square but outside the circle, but that isn't the shaded area.

Instead, think about it like this:

The shaded area is the area of the square (6 * 6) minus the area of the quarter circle.


Yeah iv found the area in the square. Then the area in the circle . Then taken them away to be left with the four parts, one of them being the shaded region so I divided by 4?
Reply 4
Original post by junayd1998
Yeah iv found the area in the square. Then the area in the circle . Then taken them away to be left with the four parts, one of them being the shaded region so I divided by 4?


Well, you could do that, but you haven't done the subtraction properly.

14436π108π144 - 36\pi \neq 108\pi. Instead, 14436π144 - 36\pi is as simplified as possible (bar factorisation).
Reply 5
Original post by Zacken
Well, you could do that, but you haven't done the subtraction properly.

14436π108π144 - 36\pi \neq 108\pi. Instead, 14436π144 - 36\pi is as simplified as possible (bar factorisation).


huh :s-smilie::frown: I'm so done with maths.
Reply 6
Original post by junayd1998
huh :s-smilie::frown: I'm so done with maths.


Well, yeah. π\pi is just a number and 36π36\pi is the number 36 multiplied by the number pi.

Do you think that 5(2×2)=(53)×2=2×25 - (2\times 2) = (5-3) \times 2 = 2\times 2? :s-smilie:
Reply 7
Original post by Zacken
Well, yeah. π\pi is just a number and 36π36\pi is the number 36 multiplied by the number pi.

Do you think that 5(2×2)=(53)×2=2×25 - (2\times 2) = (5-3) \times 2 = 2\times 2? :s-smilie:


So could you just leave it as: x = 144-36pi / 4 ?
Reply 8
Original post by junayd1998
So could you just leave it as: x = 144-36pi / 4 ?


Well, simplify it down a bit to x=144436π4=369πx = \frac{144}{4} - \frac{36\pi}{4} = 36 - 9\pi
Reply 9
Original post by Zacken
Well, simplify it down a bit to x=144436π4=369πx = \frac{144}{4} - \frac{36\pi}{4} = 36 - 9\pi


Fair enough yeah i get it now thanks for the help.
Reply 10
Original post by junayd1998
Fair enough yeah i get it now thanks for the help.


Cheers.

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