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translating horizontally a graph of cubic function

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1. Hi Guys.
I have a certain function f(x) that crosses y-axis at the point (0,12) and i move it 2 units horizontally f(x-2) in the positive direction, does the y intercept become (2,12)?? i get a value of y intercept at (0,126) in the new equation tho when i plug in zero for x to find value of y.
im not sure which one is the new y intercept, (0,126) or (2,12)? thanks
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2. (Original post by Alen.m)
Hi Guys.
I have a certain function f(x) that crosses y-axis at the point (0,12) and i move it 2 units horizontally f(x-2) in the positive direction, does the y intercept become (2,12)?? i get a value of y intercept at (0,126) in the new equation tho when i plug in zero for x to find value of y.
im not sure which one is the new y intercept, (0,126) or (2,12)? thanks
Does a y-intercept of (2, 12) make sense? Think about it - what is the definition of a y-intercept? It's when x = 0.

So does saying that when x=0, we have ( x=2 and y = 12)?

When you translate the function, the point (-2, 126) becomes (0, 126) which is your y-intercept.
3. (Original post by Zacken)
Does a y-intercept of (2, 12) make sense? Think about it - what is the definition of a y-intercept? It's when x = 0.

So does saying that when x=0, we have ( x=2 and y = 12)?

When you translate the function, the point (-2, 126) becomes (0, 126) which is your y-intercept.
i was gonna remove the thread the minute after i've posted this thread but forgot lol such stupid question i've asked
4. (Original post by Alen.m)
i was gonna remove the thread the minute after i've posted this thread but forgot lol such stupid question i've asked
It's not a stupid question.

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