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# Maths AS past paper questions (C1 and C2)

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So I did (a) but couldn't solve (b) and (c)?

I couldn't solve this question..

This one too ..
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2. f(x-1) =to the right 1

So I did (a) but couldn't solve (b) and (c)?
Write out u1 to u9 - what pattern can you spot?

This one too ..
5. (Original post by Zacken)
I don't know how to solve (a),(b)and (c) ??
I don't know how to solve (a),(b)and (c) ??
(a) is the cosine curve shifted pi/3 to the right; there's not much I can do to explain it, you should know your trig graphs and your function transformations.

(b) is just (which you should know how to solve) and then back-substitute and solve for .

(c) is just (Which you should know how to solve, one of the solutions is ) and then back-sub and solve for .

Perhaps you need to work on your concepts more before moving on to past papers?

So I did (a) but couldn't solve (b) and (c)?

I couldn't solve this question..

This one too ..
I got 40 and 5/8 for the logarithm question.
8. (Original post by Funnycatvideos)
I got 40 and 5/8 for the logarithm question.
Yeah, I actually just solved it now!!
Thank you!!
Yeah, I actually just solved it now!!
Thank you!!
You're very welcome.
10. (Original post by Zacken)
(a) is the cosine curve shifted pi/3 to the right; there's not much I can do to explain it, you should know your trig graphs and your function transformations.

(b) is just (which you should know how to solve) and then back-substitute and solve for .

(c) is just (Which you should know how to solve, one of the solutions is ) and then back-sub and solve for .

Perhaps you need to work on your concepts more before moving on to past papers?
Yeaah you're right!! Thaaank you!!

So I did (a) but couldn't solve (b) and (c)?

I couldn't solve this question..

This one too ..
For the Geometric sequences:
a)You use ar^n-1 a=300 r=1.05 n=24 so: 300*(1.05)^23=921.46=922 phones
b)You use the summation formula. I substituted the values in and I got 13351
c) You have to use ar^n-1 again:
300*1.05^N-1>3000
1.05^N-1>10
Take logs:
(N-1)log1.05>log10
N-1>log10/log1.05
N-1>47.19....
N>48.19...
N>48
12. (Original post by Funnycatvideos)
For the Geometric sequences:
a)You use ar^n-1 a=300 r=1.05 n=24 so: 300*(1.05)^23=921.46=922 phones
b)You use the summation formula. I substituted the values in and I got 13351
c) You have to use ar^n-1 again:
300*1.05^N-1>3000
1.05^N-1>10
Take logs:
(N-1)log1.05>log10
N-1>log10/log1.05
N-1>47.19....
N>48.19...
N>48
Thanks

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