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Ocr C4 june 2012

Hey.
Im a bit confused on question 5(ii).
If the the vector is -b wouldnt it be drawn the other way such that AOB from part (i) is no longer the included angle?
https://983c9f06eb1f75af6e83364e092b06f1cb5c4277.googledrive.com/host/0B1ZiqBksUHNYZzd2VHZlOXdqZlE/June%202012%20QP%20-%20C4%20OCR.pdf
Thanks
Reply 1
Original post by SamuelN98
Hey.
Im a bit confused on question 5(ii).
If the the vector is -b wouldnt it be drawn the other way such that AOB from part (i) is no longer the included angle?
https://983c9f06eb1f75af6e83364e092b06f1cb5c4277.googledrive.com/host/0B1ZiqBksUHNYZzd2VHZlOXdqZlE/June%202012%20QP%20-%20C4%20OCR.pdf
Thanks


I'm not sure whether you're aware of the fact that AB=OBOA\vec{AB} = \vec{OB} - \vec{OA}. That is, the ab\mathbf{a}-\mathbf{b} means the line connecting the points a\mathbf{a} to b\mathbf{b}.

I've written up a long explanation of why the above is true here.

(BTW, why have you been ignoring the replies to your threads? Such as here, here, here and here. Just to let you know, if you understood someones reply, it's good practice to reply and let them know that you've understood! :smile: )
Reply 2
Original post by Zacken
I'm not sure whether you're aware of the fact that AB=OBOA\vec{AB} = \vec{OB} - \vec{OA}. That is, the ab\mathbf{a}-\mathbf{b} means the line connecting the points a\mathbf{a} to b\mathbf{b}.

I've written up a long explanation of why the above is true here.

(BTW, why have you been ignoring the replies to your threads? Such as here, here, here and here. Just to let you know, if you understood someones reply, it's good practice to reply and let them know that you've understood! :smile: )


Thanks for explaining it, all is now clear.
(And ill make sure i reply in future,)
Reply 3
Original post by SamuelN98
Thanks for explaining it, all is now clear.
(And ill make sure i reply in future,)


Great, awesome! Good luck with your revision! :biggrin:

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