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pV=1/3*Nm<c^2>, Deriving the Gas Law

The particle in a box derivation for pV=(1/3)*Nm<c^2>
the time is 2l/v
Force = Impulse/Time
Impulse is 2mv but the time given above is not the time for the interaction with a wall, but for it to leave the wall and return again to the wall...
Any Help?
Thanks
Original post by Saksun Young
The particle in a box derivation for pV=(1/3)*Nm<c^2>
the time is 2l/v
Force = Impulse/Time
Impulse is 2mv but the time given above is not the time for the interaction with a wall, but for it to leave the wall and return again to the wall...
Any Help?
Thanks


Well we don't know how long the actual interaction with the wall takes, but we do know that it takes 2L/v to travel the length of the box twice and we also know the momentum change in that time is -2mv. The ideal gas is a very simple model, hence why it only applies to a few physical systems

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