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C4 parametric domain

A curve has parametric equations x=2cott,y=2sin2t,0<tπ2x = 2\cot t, y = 2\sin^{2}t, 0 < t\leq \frac{\pi}{2}. Find a cartesian equation of the form and state the domain on which the curve is defined.

I've found the cartesian equation y=8x2+4\displaystyle y = \frac{8}{x^{2}+4}.

Now here's where my problem lies - my teacher said that the curve is valid for all real values for xx and he docked a mark at first, but clearly the range of tt being restricted would mean that this can't hold true. He later took a look at the problem and he later agreed with me.

Wouldn't the domain be x0,xRx \geq 0, x \in \mathbb{R}? This is what I initially wrote on my paper.
Reply 1
Original post by Ayman!


Wouldn't the domain be x0,xRx \geq 0, x \in \mathbb{R}? This is what I initially wrote on my paper.


Yep, that's fine. :yep:
(edited 7 years ago)
if you look at this graph you can see that you are right....

Reply 3
Original post by Zacken
Not greater than or equal to - strict inequality. But otherwise - yeah.



Why strict? I thought we're letting t=π2t = \frac{\pi}{2} so cott\cot t can be 0?

Original post by the bear
if you look at this graph you can see that you are right....


Thank you, this is how I looked at it initially.
Reply 4
Original post by Ayman!
Why strict? I thought we're letting t=π2t = \frac{\pi}{2} so cott\cot t can be 0?


Edited my answer before you replied. :tongue:

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