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Integration Help

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Original post by Zacken
Because it's just a constant.


Last Question:
And the 1 is not a constant because?
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Zacken
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Original post by JKITFC
Last Question:
And the 1 is not a constant because?


It is a costant.

The whole of 1/(b-a) is a constant. The t comes from integrating, you take the whole constant 1/(b-a) and multiply it by t.

Then, call f(t) = t/(b-a) and compute f(x) - (a)

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