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# Integration Help

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1. (Original post by Zacken)
Because it's just a constant.
Last Question:
And the 1 is not a constant because?
2. (Original post by JKITFC)
Last Question:
And the 1 is not a constant because?
It is a costant.

The whole of 1/(b-a) is a constant. The t comes from integrating, you take the whole constant 1/(b-a) and multiply it by t.

Then, call f(t) = t/(b-a) and compute f(x) - (a)

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