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Edexcel Maths Higher Calculator Paper - How was it?
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For the mean question, it was like:
The mean number of 8 somethings is 41.
The mean number of 2 somethings is 29.
What is the mean of the other 6?
You multiply 8 by 41 to get 328.
You mutliply 2 by 29 to get 58.
You take the difference between 328 and 58 to get the actual amount of the other 6, which is 270.
You then divide 270 by 6 to get the mean of the 6 somethings which was 45.
So the answer is 45.
The mean number of 8 somethings is 41.
The mean number of 2 somethings is 29.
What is the mean of the other 6?
You multiply 8 by 41 to get 328.
You mutliply 2 by 29 to get 58.
You take the difference between 328 and 58 to get the actual amount of the other 6, which is 270.
You then divide 270 by 6 to get the mean of the 6 somethings which was 45.
So the answer is 45.
any signs of an electronic version of the paper? dont even know where to start looking. either of the edexcel ones would make me a happy bunny.
would get a spare out of school but dont have a scanner.
would get a spare out of school but dont have a scanner.
hbk91
If that's the case, I'm pretty sure you would have got an A*.
After evaluating my answers compared to everyone on TSR, I reckon I would have got 90/100 for Paper 5 and about 85/90 for Paper 6. I seriously don't think the grade boundaries will be ludicrously high. It'll be shocking if they are.
After evaluating my answers compared to everyone on TSR, I reckon I would have got 90/100 for Paper 5 and about 85/90 for Paper 6. I seriously don't think the grade boundaries will be ludicrously high. It'll be shocking if they are.
Phew, that's a relief, so I'm definetly in for an A at least then.
On a brighter note, I've just been accepted into NAGTY. The National Academy for Gifted and Talented Youth. WOOOT.
Guess that means I'm gifted and talented then...
hbk91
If that's the case, I'm pretty sure you would have got an A*.
After evaluating my answers compared to everyone on TSR, I reckon I would have got 90/100 for Paper 5 and about 85/90 for Paper 6. I seriously don't think the grade boundaries will be ludicrously high. It'll be shocking if they are.
After evaluating my answers compared to everyone on TSR, I reckon I would have got 90/100 for Paper 5 and about 85/90 for Paper 6. I seriously don't think the grade boundaries will be ludicrously high. It'll be shocking if they are.
I'm guessing you mean 85/100 for paper 6?
Hippysnake
Phew, that's a relief, so I'm definetly in for an A at least then.
On a brighter note, I've just been accepted into NAGTY. The National Academy for Gifted and Talented Youth. WOOOT.
Guess that means I'm gifted and talented then...
On a brighter note, I've just been accepted into NAGTY. The National Academy for Gifted and Talented Youth. WOOOT.
Guess that means I'm gifted and talented then...
I've never understood what that is.
What purpose does it serve?Time to go over some of these.
For the last question, there was a much simpler way of doing it. Basically, the new circle on the base is going to be mathematically similar by a ratio of (216/360) or 1 : 0.6
0.6*15 = 9
Looking at 9 and 15 and knowing pythagoras, you shouldn't even need a calculator. It's a 345 triangle. The answer, of course, was 12cm.
For the hidden quadratics question, the fractions simplified to x²-6x+9=0. You then factorise it to two numbers which add to make -6 and multiply to make +9. Looking at the question there was only one answer, which threw me before I got to that point. But the factorisation comes to (x-3)(x-3), so the only answer is that x=3.
For the straight line, it's a lot simpler than it looks. If you draw two arcs from A and B, the line that connects to where they touch will be of equal distance from A and B.
For the mean of the numbers question, let us turn the question into algebra.
a+b+c+d+e+f+g+h/8 = 41
a+b/2= 29
Get rid of the denominators:
a+b+c+d+e+f+g+h=328
a+b=58
Then do a simultaneous equation:
a+b+c+d+e+f+g+h-a-b=328-58
c+d+e+f+g+h=270
270/6 = 45
As for how I did, I knew the answer to ever single question, so providing my working out is correct, I might even be able to think of 100%.
For the last question, there was a much simpler way of doing it. Basically, the new circle on the base is going to be mathematically similar by a ratio of (216/360) or 1 : 0.6
0.6*15 = 9
Looking at 9 and 15 and knowing pythagoras, you shouldn't even need a calculator. It's a 345 triangle. The answer, of course, was 12cm.
For the hidden quadratics question, the fractions simplified to x²-6x+9=0. You then factorise it to two numbers which add to make -6 and multiply to make +9. Looking at the question there was only one answer, which threw me before I got to that point. But the factorisation comes to (x-3)(x-3), so the only answer is that x=3.
For the straight line, it's a lot simpler than it looks. If you draw two arcs from A and B, the line that connects to where they touch will be of equal distance from A and B.
For the mean of the numbers question, let us turn the question into algebra.
a+b+c+d+e+f+g+h/8 = 41
a+b/2= 29
Get rid of the denominators:
a+b+c+d+e+f+g+h=328
a+b=58
Then do a simultaneous equation:
a+b+c+d+e+f+g+h-a-b=328-58
c+d+e+f+g+h=270
270/6 = 45
As for how I did, I knew the answer to ever single question, so providing my working out is correct, I might even be able to think of 100%.
The Quadratics questions was 1 and 9...wasn't it?
Princess
I'm guessing you mean 85/100 for paper 6?
What are the odds that the exam A* grade boundaries will be around 90 for both papers? Little I hope.
RobJonesxx
any signs of an electronic version of the paper? dont even know where to start looking. either of the edexcel ones would make me a happy bunny.
would get a spare out of school but dont have a scanner.
would get a spare out of school but dont have a scanner.
I would actually like to see it too.
But do you really think there is a copy of it anywhere?
sonicandfffan
Time to go over some of these.
For the last question, there was a much simpler way of doing it. Basically, the new circle on the base is going to be mathematically similar by a ratio of (216/360) or 1 : 0.6
0.6*15 = 9
Looking at 9 and 15 and knowing pythagoras, you shouldn't even need a calculator. It's a 345 triangle. The answer, of course, was 12cm.
For the last question, there was a much simpler way of doing it. Basically, the new circle on the base is going to be mathematically similar by a ratio of (216/360) or 1 : 0.6
0.6*15 = 9
Looking at 9 and 15 and knowing pythagoras, you shouldn't even need a calculator. It's a 345 triangle. The answer, of course, was 12cm.
That's the way I did it. I knew straight away I had to use pythagoras but that it wouldn't work taking 15^2 from 15^2, so I multiplied one by 216/360 and got 9 and did pythagoras from there.
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