Original post by jonnypdot
Q1c can someone help me on this i thought for poisson distribution events were independent can someone clear up this issue i got?
Post a picture or link to your question.
They are independent, but you are calculating a conditional probability here.
P(1 on first day, 3 on second day | (given) 4 in 2 days).
Original post by Zacken
They are independent, but you are calculating a conditional probability here.
P(1 on first day, 3 on second day | (given) 4 in 2 days).
P(1 on first day, 3 on second day | (given) 4 in 2 days).
so can u give me a word equation of what to calculate?
Original post by jonnypdot
so can u give me a word equation of what to calculate?
Probability X = 1 * Probability X=3 all divided by Probability X=4
Original post by Zacken
Probability X = 1 * Probability X=3 all divided by Probability X=4
so P(B|A) = P(AnB) / P(A)
P(AnB) = P(B) because event B has a total of 4 car and so does event A
Original post by jonnypdot
so P(B|A) = P(AnB) / P(A)
P(AnB) = P(B) because event B has a total of 4 car and so does event A
P(AnB) = P(B) because event B has a total of 4 car and so does event A
Where A is the event "4 cars" and B is the event "1 car on day 1 and 3 cars on day 2", then yes.
Original post by Zacken
Where A is the event "4 cars" and B is the event "1 car on day 1 and 3 cars on day 2", then yes.
ok thank you
Original post by jonnypdot
ok thank you
No problem.
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