You are Here: Home >< Maths

# M2 help

Announcements Posted on
Last day to win £100 of Amazon vouchers - don't miss out! Take our quick survey to enter 24-10-2016
1. Can someone explain 4ii to me I just don't get it.

Like there is no point giving me hints, I don't get what is going on.
Attached Images

2. (Original post by Super199)
Can someone explain 4ii to me I just don't get it.

Like there is no point giving me hints, I don't get what is going on.
Since you've done the first part, you know the general set up.

For the second part there is an additional mass added to the string at its midpoint.

Then tension in the AP part of the string will be what's necessary for the two masses to move in a circle.
3. (Original post by ghostwalker)
Since you've done the first part, you know the general set up.

For the second part there is an additional mass added to the string at its midpoint.

Then tension in the AP part of the string will be what's necessary for the two masses to move in a circle.
Is the tension in the string the same even though it is only half the length now?
4. (Original post by Super199)
Is the tension in the string the same even though it is only half the length now?
Same as what? It's different to the first part.

The length of the portion of the string does not effect the tension. It's only the masses and their position (and the rate of revolution) that effects the tension. And there are now two masses.
5. (Original post by ghostwalker)
Same as what? It's different to the first part.

The length of the portion of the string does not effect the tension. It's only the masses and their position (and the rate of revolution) that effects the tension. And there are now two masses.
Hmm I think I've got it cheers.

Do you mind helping with 6ii.

I think I have the time for p, but I don't understand how to get the time for q.

http://www.ocr.org.uk/Images/57767-q...echanics-2.pdf
6. (Original post by Super199)
Hmm I think I've got it cheers.

Do you mind helping with 6ii.

I think I have the time for p, but I don't understand how to get the time for q.

http://www.ocr.org.uk/Images/57767-q...echanics-2.pdf
Q was launched when P was above A.

So, how long did it take for P to get to the point above A? Knock that off the total flight time fro P, and you have the flight time for Q.
7. (Original post by ghostwalker)
Q was launched when P was above A.

So, how long did it take for P to get to the point above A? Knock that off the total flight time fro P, and you have the flight time for Q.
Time for P to get to A.

S = 250
u = 86sin62.3
v = ?
a = -9.8
t = ?
S= ut -4.9t^2
250 = 86sin62.2t - 4.9t^2
t = 10.8 s

Time from P to the ground
s = -250
u = 30
v =?
a = -9.8
t = ?
-250 = 30t - 9.8t^2
t = 6.8s

Total time = 17.6
17.6 - 16.8 = 10.8s
But where does the time for p - 15.5s come from?
8. (Original post by Super199)
Time for P to get to A.

S = 250
u = 86sin62.3
v = ?
a = -9.8
t = ?
S= ut -4.9t^2
250 = 86sin62.2t - 4.9t^2
t = 10.8 s
IF the vertical speed initially was 86ms^-1 (which it isn't - it's less), then in 10 seconds it's vertical velocity would have become negative i.e 86-10g. But it isn't, it's 30 upwards, so t=10.8 can't be right.

Time from P to the ground
s = -250
u = 30
v =?
a = -9.8
t = ?
-250 = 30t - 9.8t^2
t = 6.8s
If you're going to work out the time from P to the ground, then this is the actual time of flight of Q.
9. (Original post by ghostwalker)
IF the vertical speed initially was 86ms^-1 (which it isn't - it's less), then in 10 seconds it's vertical velocity would have become negative i.e 86-10g. But it isn't, it's 30 upwards, so t=10.8 can't be right.

If you're going to work out the time from P to the ground, then this is the actual time of flight of Q.
Hmm Im not too sure. I've attached the mark scheme if you want to have a look.
Attached Images

## Register

Thanks for posting! You just need to create an account in order to submit the post
1. this can't be left blank
2. this can't be left blank
3. this can't be left blank

6 characters or longer with both numbers and letters is safer

4. this can't be left empty
1. Oops, you need to agree to our Ts&Cs to register

Updated: May 12, 2016
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Today on TSR

### How does exam reform affect you?

From GCSE to A level, it's all changing

Poll
Useful resources

### Maths Forum posting guidelines

Not sure where to post? Read here first

### How to use LaTex

Writing equations the easy way

### Study habits of A* students

Top tips from students who have already aced their exams