I didn't know how to answer this question could someone please break it down for me on how to do it?
A spring extends by 9 cm when a force of 6 N is applied. The limit of proportionality is not exceeded. Another identical spring is joined end to end with this spring and a force of 4 N is applied. What is the extension for the pair of springs?
the way i worked it out it: extension = 9 force = 6 F=k delta L 6= 9k k= 2/3
when springs are in series the force is equal throughout so on each spring will be a force of 4N so for one spring: f= k delta L 4 = 2/3 delta L delta L = 6 so for 2 springs 6*2=12cm
The spring constant is the same. so the spring constant is 2/3. So the new spring is connected in series so therefore the total extension should be 9+x. Using f=kx, we can substitute 4=2/3 x (9+x). when you solve this you get x=3. therefore the total extension of the pair of strings in series is 9+3=12cm