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# AQA A Level Maths Core 2 - 25th May 2016 [Exam Discussion]

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1. (Original post by BenAtkinson)
UN-OFFICIAL MARK SCHEME.
Of what I can remember..

1. b) a=2
2. b) x=-0.861
c) reflection in y-axis
3. a) 3x^-1/2 - 1
b) y=6
c) y + 2x = 13
d) k = 5.5
4. b) d = -2, a = 28
c) Sum to 21 - sum to 3. Can't remember exact.
5. b) area = 19.9
c) perimeter = 13.8 (something like that)
6. a) 65.6
b) i) translation (0,5)
ii) stretch in X-direction 1/3 sf
7. b) -1648
8. b) can't remember! Tan(X) = 1 and tan(X) =-5/4
c) lowest = 2, when theta = pi
9. a) c^(m/2 +6n)
b) X = 5/2

Posted from TSR Mobile
I think I got the same for all. 9 was 3^(m/2 -6n)

For 4 U12 was 6
And I think I got -336 for one question
2. (Original post by Shehryar01)
Don't remember the answer but the method i used was to half the area of triangle and then use that to find radius by the area of sector then subbed r into equation of arc length then found perimeter. It was an easy 6 marks. and i did get radius in decimal so the answer was in decimal as well
ohhh thats how you do it, i was completely stumped by that question i just wrote area of triangle and half it and i couldnt do the rest...now i feel really stupid
3. (Original post by viktorh)
I got:

65.6 for the trapezium rule question
6 for U12 near the end
and for the sigma question at the end I got 90???

anyone get any of these
All the same
4. (Original post by BenAtkinson)
UN-OFFICIAL MARK SCHEME.
Of what I can remember..

1. b) a=2
2. b) x=-0.861
c) reflection in y-axis
3. a) 3x^-1/2 - 1
b) y=6
c) y + 2x = 13
d) k = 5.5
4. b) d = -2, a = 28
c) Sum to 21 - sum to 3. Can't remember exact.
5. b) area = 19.9
c) perimeter = 13.8 (something like that)
6. a) 65.6
b) i) translation (0,5)
ii) stretch in X-direction 1/3 sf
7. b) -1648
8. b) can't remember! Tan(X) = 1 and tan(X) =-5/4
c) lowest = 2, when theta = pi
9. a) c^(m/2 +6n)
b) X = 5/2
Posted from TSR Mobile
You're answers to 1,2,3,5,6,7,8,9B) seem familiar but not 9 or 4 :/
Think I got a=-28 for 4)b and d=34
I though 9)a) was 3^(n/12m) (possibly with m and n the other way round)
5. Wow that's extremely frustrating >.> I worked out the arc length aswell just didn't add it. Likely 5 marks for method atleast :L
6. (Original post by Alfie Oliver)
Did anyone else get the binomial expansion answer as something like -1000 something it was like -1280 idk tho something around there?
Same here. Something like -1260 or -1280.
7. What does everyone think the grade boundaries will be like? Lower or higher than last year?
8. (Original post by Alfie Oliver)
Did anyone else get the binomial expansion answer as something like -1000 something it was like -1280 idk tho something around there?
I got this!!
9. (Original post by BenAtkinson)
UN-OFFICIAL MARK SCHEME.
Of what I can remember..

1. b) a=2
2. b) x=-0.861
c) reflection in y-axis
3. a) 3x^-1/2 - 1
b) y=6
c) y + 2x = 13
d) k = 5.5
4. b) d = -2, a = 28
c) Sum to 21 - sum to 3. Can't remember exact.
5. b) area = 19.9
c) perimeter = 13.8 (something like that)
6. a) 65.6
b) i) translation (0,5)
ii) stretch in X-direction 1/3 sf
7. b) -1648
8. b) can't remember! Tan(X) = 1 and tan(X) =-5/4
c) lowest = 2, when theta = pi
9. a) c^(m/2 +6n)
b) X = 5/2

Posted from TSR Mobile
for 6bii i got stretch in y-direction scale factor 3
10. (Original post by jordanwu)
What does everyone think the grade boundaries will be like? Lower or higher than last year?
For a c2 test i found that pretty easy so I'd assume they'll go up
11. (Original post by yelash)
You're answers to 1,2,3,5,6,7,8,9B) seem familiar but not 9 or 4 :/
Think I got a=-28 for 4)b and d=34
I got same for 4 as in unofficial MS and for 9 there was a number instead of c which i think was 3
12. (Original post by jordanwu)
What does everyone think the grade boundaries will be like? Lower or higher than last year?
i think it may be just a bit higher than last years
13. (Original post by MotorboatMyGoat)
I think I got the same for all. 9 was 3^(m/2 -6n)

For 4 U12 was 6
And I think I got -336 for one question
I think it should be m/2 -6n as when you divide you take away powers?
14. For the 3(x^3 + 1)^1/2 translation, I took the 3 into the square root and times it all by factor nine, this gave me stretch in X direction sf 1/9??
15. (Original post by BenAtkinson)
UN-OFFICIAL MARK SCHEME.
Of what I can remember..

1. b) a=2
2. b) x=-0.861
c) reflection in y-axis
3. a) 3x^-1/2 - 1
b) y=6
c) y + 2x = 13
d) k = 5.5
4. b) d = -2, a = 28
c) Sum to 21 - sum to 3. Can't remember exact.
5. b) area = 19.9
c) perimeter = 13.8 (something like that)
6. a) 65.6
b) i) translation (0,5)
ii) stretch in X-direction 1/3 sf
7. b) -1648
8. b) can't remember! Tan(X) = 1 and tan(X) =-5/4
c) lowest = 2, when theta = pi
9. a) c^(m/2 +6n)
b) X = 5/2

Posted from TSR Mobile
Why did you get tan(X)=1 and tan(X)=-5/4 for 8b? I only got tan(X)=-5/4 and got 2 solutions from it
16. (Original post by Poppy1098)
I think it should be m/2 -6n as when you divide you take away powers?
Dam I think I divided the powers :/// stupid me. How many marks was that?
17. (Original post by jordanwu)
Oh crap I got c^m/2 -6n :/
I think it was -6n, because it's a division, right??
18. (Original post by gardenGnostic)
I got like ~3.41 for the arc length for the triangle and something like ~5.86 for r. I think you had to say that 1/2 r^2 x = 19.9(area of triangle)-1/2 r^2 x, therefore r^2 x = 19.9. You already know x, so substitute it in and get r^2 to be ~34 and r = 5.86 ish. Final perimeter should be about 13.7 or 13.8 depending on how you've rounded in the question.

Of course, I could be completely wrong
No, i got that too
19. (Original post by Ben4444)
Why did you get tan(X)=1 and tan(X)=-5/4 for 8b? I only got tan(X)=-5/4 and got 2 solutions from it
Because one of the brackets that the question gave was (1-tanx), therefore tanx =1 is a thing
20. (Original post by Ben4444)
Why did you get tan(X)=1 and tan(X)=-5/4 for 8b? I only got tan(X)=-5/4 and got 2 solutions from it
the question gave us a factorised quadratic so in first (1-tanx) it was one solution and the other one you had to sub in tanx=-5/4 from previous question and equal it to zero therefore 2 solutions from each so 4 in total

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