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# Edexcel International A level (IAL): Physics Unit 6 (WPH06) - 19th May, 2016 - PM

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1. (Original post by jasonqqqq)
no 1 uncertainity is about 0.014 i use the gradent and multyply 0.002mthen %u is 2.2%
Did you draw the worst fit line?
2. i draw a very good best fit line in the last question... almost all the points can on it
3. Btw, can I quote % uncertainty to 1SF instead of 2SF?
4. (Original post by jasonqqqq)
i draw a very good best fit line in the last question... almost all the points can on it
How do you find uncertainty in question 1 using gradient?
5. i found the in mark scheme almost all of them are 2sf so i have written 2 sf
6. just use 7.14X 0.002 = 0.0014N
7. (Original post by jasonqqqq)
just use 7.14X 0.002 = 0.0014N
Why?
8. uncertainity / uncertainity = constant

so use constant to calculate the another uncertainity..

but i am not sure is it correct..
9. How about precaution for the capacitor question?
10. (Original post by tgygt)
How about precaution for the capacitor question?
In a past paper the answer was to check the orientation of the capacitor, to prevent overheating I believe
11. Correct orientation to avoid over heating, this was in a past paper
12. (Original post by oli4rg)
Correct orientation to avoid over heating, this was in a past paper
This is for preventing it from damage
13. (Original post by tgygt)
This is for preventing it from damage
Oh, sorry- because I was taking readings ever 5 seconds I said that the stopwatch should be close to the voltmeter to try reduce errors formed when taking simultaneous readings
14. (Original post by oli4rg)
Oh, sorry- because I was taking readings ever 5 seconds I said that the stopwatch should be close to the voltmeter to try reduce errors formed when taking simultaneous readings
Why would you use stopwatch?
This experiment is not the same with the previous one in past paper
15. (Original post by tgygt)
Why would you use stopwatch?
This experiment is not the same with the previous one in past paper
I was taking the voltage levels per 5 seconds whilst charging so V1 then again for V2 so I had multiple results to plot but idk ...
16. For the uncertainity in question 1 I found the max possible value of W1 minus minimum possible value . and then divide by 2
I got something like 0.015N
17. (Original post by Owais.ik)
For the uncertainity in question 1 I found the max possible value of W1 minus minimum possible value . and then divide by 2
I got something like 0.015N
same approach, but i forgot to divide it by two, is that ok? cuz full range for uncertainty is sometimes ok😵
18. (Original post by Kev__)
same approach, but i forgot to divide it by two, is that ok? cuz full range for uncertainty is sometimes ok😵
Yea It's okay!
19. (Original post by Kev__)
same approach, but i forgot to divide it by two, is that ok? cuz full range for uncertainty is sometimes ok😵
Well I have seen papers with uncertainity as either full or half range. So there's chance that it is correct
20. it said sth like the uncertainty of l is 0.2 mm as i recall

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Updated: May 22, 2016
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