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# FP1 matrix

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1. for part C, isnt it QT' = T ? but it is wrong and i cant get the answer, can someone help me?
2. (Original post by alesha98)
for part C, isnt it QT' = T ? but it is wrong and i cant get the answer, can someone help me?
Well T is a triangle and not a matrix.

I agree that QT' = T. And we know that to go from T to T' we need to use P and to go from T' to T we need to use P^(-1).

So PT = T^(-1).

So QT' = T is QPT = T. This gets you Q = P^(-1).
3. (Original post by Zacken)
Well T is a transformation and not a matrix.

I agree that QT' = T. And we know that to go from T to T' we need to use P and to go from T' to T we need to use P^(-1).

So QT' = T is QP^(-1) = P. This gets you Q = PP.
So from what you are saying, should it be QT'=T, but PT = T'. So if i sub PT = T' in to QT' = T, i will get QPT = T, then QP=I, Q = P-1?
4. (Original post by alesha98)
So from what you are saying, should it be QT'=T, but PT = T'. So if i sub PT = T' in to QT' = T, i will get QPT = T, then QP=I, Q = P-1?
Yes, sorry. Slip up on my part, that's correct.
5. (Original post by Zacken)
Yes, sorry. Slip up on my part, that's correct.
Thankyou , i got another question, can you help me as well please?
6. (Original post by alesha98)
Thankyou , i got another question, can you help me as well please?
Sure, post it.
7. (Original post by Zacken)
Sure, post it.
I totally struggled to do 9(d), How to undo arg?
8. (Original post by alesha98)
I totally struggled to do 9(d), How to undo arg?
There's no need to undo the arg. You just need to put in the value of w to get: .

We know that if then it must mean that the imaginary part of z has to equal the real part of z. Because, well the half-line is y = x. The diagonal line passing through the centre. That is Im(z) =Re(z).

So we need .
9. (Original post by Zacken)
There's no need to undo the arg. You just need to put in the value of w to get: .

We know that if then it must mean that the imaginary part of z has to equal the real part of z. Because, well the half-line is y = x. The diagonal line passing through the centre. That is Im(z) =Re(z).

So we need .
Oh ... It is a tricky question for me, but thanks for your explanation, it makes sense to me now
10. (Original post by alesha98)
Oh ... It is a tricky question for me, but thanks for your explanation, it makes sense to me now
No problem. :-)

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