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# OCR Physics A Breadth of Physics (24th May 2016) Discussion

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1. (Original post by NthnBrwn)
i got 12 mW, because energy is conserved at a junction, the power dissipated by the resistor was 12mW.
what were the other opts?
2. (Original post by ZacS)
I think it was C because when it crossed the zero line again that means is accelerating towards the ground and at D it hit the ground
(Original post by maryamkhawaja)
it said max displ after it bounces once.
I agree that it was C. It was the only logical answer. The max displacement is always going to be when the velocity is 0.
3. (Original post by maryamkhawaja)
it said max displ after it bounces once.
Isn't that point B then where it was negative since at 0 it means it returned to the original position, I don't know.
4. (Original post by Parhomus)
I just wrote measure mass on scale. W=mg , A =pid^2/4 then P=W/A. To make it more precise I said repeat the measurement and average it.
That's exactly what I put, but I'm not sure whether they wanted us to talk about using a newtonmeter thingymuboby.
5. (Original post by Parhomus)
Isn't that point B then where it was negative since at 0 it means it returned to the original position, I don't know.
I put that Aswell because A was where it bounced first
6. Question paper pdf anyone pleaseeee!
7. (Original post by maryamkhawaja)
how?
I believe I used the wavelength to find the frequency (assuming v = 3 x 10^8)
I then used E=hf to find the total energy and divided this value by the energy of one electron (1.602 x 10^-19J)
I cant completely remember but I think this is what I did
8. (Original post by maryamkhawaja)
what were the other opts?
18 mW was another option I guessed B (12 mW)
9. I got 7520 for the density because I rounded early, will that drop me marks?
10. (Original post by richpanda)
I agree that it was C. It was the only logical answer. The max displacement is always going to be when the velocity is 0.
How many marks do you think I'll lose if i forgot the negative sign in the momentum question (how many marks was that question?) Also how many marks was the mean drift velocity question, do u think?
11. (Original post by flamingllama)
I believe I used the wavelength to find the frequency (assuming v = 3 x 10^8)
I then used E=hf to find the total energy and divided this value by the energy of one electron (1.602 x 10^-19J)
I cant completely remember but I think this is what I did
Don't u just divide the power by the energy per photon since power is energy per second.
12. i forgot to convert units for the density question and left in in kg/cm3 how many marks would that lose
13. Such a weird paper...
14. (Original post by alex19678)
i forgot to convert units for the density question and left in in kg/cm3 how many marks would that lose
1 or maybe 2 at the very most
15. Was it just me that thought the multiple choice questions were the hardest part of the paper?
16. (Original post by AccountingHelp)
1 or maybe 2 at the very most
how many marks was it worth?
17. (Original post by Parhomus)
Don't u just divide the power by the energy per photon since power is energy per second.
It was 3 marks wasn't it?
They generally only give one or two marks if a question has so few steps
(I could be incorrect though)
18. Where can we get the model answers or smth for this paper

also when
19. (Original post by flamingllama)
It was 3 marks wasn't it?
They generally only give one or two marks if a question has so few steps
(I could be incorrect though)
I think you will get the marks for what you got as energy per photon but since photons and electrons have a one to one interaction you couldn't divide it by elementary charge. Probs 2/3
20. (Original post by Mizzeeboy)
what did you guys get for the drift velocity of the electrons I got some crazy answer of 10^7 but couldn't see where I went wrong?
i got summin like dat aswell

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