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Coordinate Geometry Core 1 tangent length help

Hi all!

I'm doing some maths revision for the core 1 exam on Wednesday and I can't seem to get the right answer for this question. The book I'm using is however frequently wrong so I was wondering whether someone else could do the question and see if we get the same answers or whether you get what's in the book. I got the length to be the square root of 57.

Find the length of the tangent from the point (2,5) to the circle x^2 + y^2 -14x - 2y+12=0

Thanks in advance
(edited 1 year ago)
Post some working then - I get root(3)
Reply 2
Original post by ghostwalker
Post some working then - I get root(3)


Will do, the book gets 5?
What was the book's answer?
I got root 3 also
Reply 5
Original post by ghostwalker
Post some working then - I get root(3)


The centre of the circle is (7,1) meaning when you have solved the equation of the circle into completed square form you the radius as 4.
I then worked out the length of the line from (2,5) to (7,1) using pythagoras and got that to be sqrt41 (25+16to give 41). Then I used pythagoras again to get the length by doing 41+16 = 57 and then square rooted that for the final length
The completed square form gave me a radius square root 38.
(edited 7 years ago)
Original post by Bigbosshead
The completed square form gave me a radius 38.


38^1/2
Reply 8
Original post by Bigbosshead
The completed square form gave me a radius 38.


But 7 squared is 49 and 1 squared is 1 and you have 34 already meaning 50-34=16? And therefore r=4?
It clearly says 12 not 34. Please post the full question word for word I feel as though you missed something out
Original post by Xenon17
It clearly says 12 not 34. Please post the full question word for word I feel as though you missed something out


Sorry yes, it is meant to be +34 and then that is the full question word for word, sorry, I got the 12 from the question below, oops!
lol
In which case the book's answer of 5 is correct.
Should be 41-16 giving 25 and root.

The distance of the point (2,5) to the centre forms the hypotenuse of the triangle, hence subtracting from the 41.
Original post by ghostwalker
Should be 41-16 giving 25 and root.

The distance of the point (2,5) to the centre forms the hypotenuse of the triangle, hence subtracting from the 41.


woah, you don't need to do this, the circle has point (7,5) at the top (because the radius is 4, and the centre is (7,1)), and the other point given was (2,5). simple as doing 7-2 = 5
(edited 7 years ago)
Original post by LewisClothier
woah, you don't need to do this, the circle has point (7,5) at the top, and the other point given was (2,5). simple as doing 7-2 = 5


Methods that work in special situations are useful, but the OP had an issue with working out the length with the more general method, and it was important they get that right. Good spot though.

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