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# vector

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1. http://prnt.sc/b4b15n

part b) is 3/4b right? could you write just that because that is one of the ways to get from O to P or do you have to write 1/4 a as well because that is another way you could get there.
2. (Original post by junayd1998)
http://prnt.sc/b4b15n

part b) is 3/4b right? could you write just that because that is one of the ways to get from O to P or do you have to write 1/4 a as well because that is another way you could get there.
no matter which route you take, the answer should be the same.
To get from O to P, you could do:
• O to A, then A to P, or
• O to B, then B to P
3. (Original post by surina16)
no matter which route you take, the answer should be the same.
To get from O to P, you could do:
• O to A, then A to P, or
• O to B, then B to P
ugh hate vectors
4. (Original post by junayd1998)
ugh hate vectors
Really? They're one of my favourite bits in maths so far
Do you understand where you went wrong in this question?
5. (Original post by surina16)
Really? They're one of my favourite bits in maths so far
Do you understand where you went wrong in this question?
Yeah, haha; you need to teach me.
6. (Original post by junayd1998)
Yeah, haha; you need to teach me.
lol post any vector questions here if you get stuck and I'm sure everyone will help out
7. (Original post by surina16)
lol post any vector questions here if you get stuck and I'm sure everyone will help out
http://prntscr.com/b4cif7 well I'm stuck on this, this is how far i got what do i do from here
8. (Original post by junayd1998)
http://prntscr.com/b4cif7 well I'm stuck on this, this is how far i got what do i do from here
Ah okay, you've done everything correctly - now all you have to do is simplify it
It's just a case of multiplying out that bracket and adding the terms together.
9. (Original post by surina16)
Ah okay, you've done everything correctly - now all you have to do is simplify it
It's just a case of multiplying out that bracket and adding the terms together.
http://prnt.sc/b4cqtu like that???
10. (Original post by junayd1998)
http://prnt.sc/b4cqtu like that???
Yes

I personally find it easier sometimes to use decimals like:
a - 0.75a + 0.75b but what you did is perfect

Now do you know how to tidy that expression up a little?
(ie. what to do with: a + -3/4a + 3/4b)
11. (Original post by surina16)
Yes

I personally find it easier sometimes to use decimals like:
a - 0.75a + 0.75b but what you did is perfect

Now do you know how to tidy that expression up a little?
(ie. what to do with: a + -3/4a + 3/4b)

http://prntscr.com/b4cu91 that?
12. No, what did you do to get to that?
What you want to do is 1 - 3/4 for the a term and then leave b as it is
13. (Original post by surina16)
No, what did you do to get to that?
What you want to do is 1 - 3/4 for the a term and then leave b as it is
Where does 1 come from ? ugh im confused
14. (Original post by junayd1998)
Where does 1 come from ? ugh im confused
you have the expression:
a + -3/4a + 3/4b

a is the same as 1a, we just don't put the 1 there as it adds no meaning.

I'm guessing we need to go over fractions?

Example 1:
2/3 - 1/6
To add/subtract fractions, you must have a common denominator.
The lowest common multiple of 3 and 6 is 6, so you want the denominator of both fractions to be 6.

2/3 can be written with 6 as the denominator if you multiply the fraction by 2/2 (you are not changing the value as 2/2 is the same as 1)
2 * 2 = 4, 3 * 2 = 6. So you get 4/6.

Now you can subtract the fractions.
4/6 - 1/6 = (4-1)/6 = 3/6 --> you can then simplify this to 1/2.

-------------------------------------------------------------------------------------------
Now can you do 1 - 3/4, and see how this would link to the question?
15. (Original post by surina16)
you have the expression:
a + -3/4a + 3/4b

a is the same as 1a, we just don't put the 1 there as it adds no meaning.

I'm guessing we need to go over fractions?

Example 1:
2/3 - 1/6
To add/subtract fractions, you must have a common denominator.
The lowest common multiple of 3 and 6 is 6, so you want the denominator of both fractions to be 6.

2/3 can be written with 6 as the denominator if you multiply the fraction by 2/2 (you are not changing the value as 2/2 is the same as 1)
2 * 2 = 4, 3 * 2 = 6. So you get 4/6.

Now you can subtract the fractions.
4/6 - 1/6 = (4-1)/6 = 3/6 --> you can then simplify this to 1/2.

-------------------------------------------------------------------------------------------
Now can you do 1 - 3/4, and see how this would link to the question?
Yeah 1/4 lmao but I don't see how it links one bit
16. (Original post by junayd1998)
Yeah 1/4 lmao but I don't see how it links one bit
because you have 1a and you want to subtract 3/4a?
Sorry I'm not very good at explaining and have no idea how else to put it??

1a - 3/4a = 1/4a

add this to the b part and you have:
1/4 + 3/4b
17. (Original post by surina16)
because you have 1a and you want to subtract 3/4a?
Sorry I'm not very good at explaining and have no idea how else to put it??

1a - 3/4a = 1/4a

add this to the b part and you have:
1/4 + 3/4b
I think I get what you mean, I think I was confused because 1a isn't a fraction like its the same as 1/1 - 3/4. I get you now i think . Thanks for your help and explanation appreciate it. Would you mind helping me on a few others? If not, its fine your probably getting sick of me trying to get my head around this.
18. (Original post by surina16)
They're one of my favourite bits in maths so far

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