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# M1 question

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1. The question is a small ring of weight W N (N being newtons) is threaded on a hrozintal curtain rail, a light inextensible string is pulling it along the rail. The Tension in the string is equal to 2w N. Show that the least value of the coefficient of friction is 0.586.

I resolved vertically and got R = 2w Sin 45 + W

Horizontally is F = 2w Cos 45, but I cant advance this any further?
2. (Original post by SunDun111)
The question is a small ring of weight W N (N being newtons) is threaded on a hrozintal curtain rail, a light inextensible string is pulling it along the rail. The Tension in the string is equal to 2w N. Show that the least value of the coefficient of friction is 0.586.

I resolved vertically and got R = 2w Sin 45 + W

Horizontally is F = 2w Cos 45, but I cant advance this any further?
I assume that w and W are supposed to be the same.

Now use F <= mu R The w's will cancel and you'll get a number.
3. (Original post by SunDun111)
The question is a small ring of weight W N (N being newtons) is threaded on a hrozintal curtain rail, a light inextensible string is pulling it along the rail. The Tension in the string is equal to 2w N. Show that the least value of the coefficient of friction is 0.586.

I resolved vertically and got R = 2w Sin 45 + W

Horizontally is F = 2w Cos 45, but I cant advance this any further?

edit: wow, okay... dat ninja
4. (Original post by Zacken)

edit: wow, okay... dat ninja
Im still stuck on this question, I sub it into F = UR formula,

I get 2W Cos 45 = U (W + 2W sin 45)

I try to get rid of the W but i keep getting 0.6 as my coefficiaent of friction, but its not supposed to be that.
5. (Original post by SunDun111)
Im still stuck on this question, I sub it into F = UR formula,

I get 2W Cos 45 = U (W + 2W sin 45)

I try to get rid of the W but i keep getting 0.6 as my coefficiaent of friction, but its not supposed to be that.
Post up a picture of what you're doing.
6. (Original post by SunDun111)
Im still stuck on this question, I sub it into F = UR formula,

I get 2W Cos 45 = U (W + 2W sin 45)

I try to get rid of the W but i keep getting 0.6 as my coefficiaent of friction, but its not supposed to be that.
https://www.wolframalpha.com/input/?...81%2B2sin45%29
7. (Original post by Zacken)
Post up a picture of what you're doing.
Thanks worked it out,
8. (Original post by SunDun111)
Im still stuck on this question, I sub it into F = UR formula,

I get 2W Cos 45 = U (W + 2W sin 45)

I try to get rid of the W but i keep getting 0.6 as my coefficiaent of friction, but its not supposed to be that.
(Original post by Zacken)

edit: wow, okay... dat ninja
I have another question,
It is A particle of weight 10n is suspended from a fixed point by a light inextensible string. A horiozontal force of 5N acts on the particle, find the tension in the string and the angle between it and the vertical,

I am only confused because it says 'fixed point' what does this mean? how would it affect how i lay out my diagram
9. (Original post by SunDun111)
I have another question,
It is A particle of weight 10n is suspended from a fixed point by a light inextensible string. A horiozontal force of 5N acts on the particle, find the tension in the string and the angle between it and the vertical,

I am only confused because it says 'fixed point' what does this mean? how would it affect how i lay out my diagram
It doesn't mean anything, it just means you hang the wait from there and "there" stayed still and doesn't move about. Just draw a string hanging from the ceiling.

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