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Edexcel IAL Core Mathematics - C12 - WMA01 - JUNE 2016

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71/64 correct answer
Reply 21
Avatar for hasi.99
hasi.99
4
Original post by Blazyy
11/64


Yea I think it was 11/64


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Original post by hasi.99
Yea I think it was 11/64
no it will be 71/64
wht finished ???
Original post by TeeEm
Has this finished already?
i got 0.33 as the area
how did u guys solve 100-3r sum question ?
Reply 26
Avatar for TeeEm
TeeEm
19
Original post by azizmansoor
wht finished ???


The search for Elvis
Reply 27
Avatar for Fadel
Fadel
16
Original post by ToxicPhantom007
how did u guys solve 100-3r sum question ?


You replace r with 1,2,3 to get a sequence. Then you'll realize that it's arithmetic with d=-3. Use the formula and that's all.
Reply 28
Avatar for Blazyy
Blazyy
3
Original post by hasi.99
Yea I think it was 11/64


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I'm pretty sure it's 11/64. My friend got the same answer.
Original post by Fadel
You replace r with 1,2,3 to get a sequence. Then you'll realize that it's arithmetic with d=-3. Use the formula and that's all.


and what did you do for area in sector question ?
angle=1.287 rad
was it shaded area or whole area of shape ?
Reply 31
Avatar for Fadel
Fadel
16
[QUOTE="hasan;65147825" Imran="Imran"]
Original post by hasi.99
Yea I think it was 11/64
no it will be 71/64


Area of triangle is 0.5*3/8*1.5 which is 0.28. Your answer is greater than the area of the triangle lol.
Reply 32
Avatar for Fadel
Fadel
16
Original post by ToxicPhantom007
and what did you do for area in sector question ?
angle=1.287 rad


I got it wrong because j didn't subtract 0.4 from radius. But you do r-0.4 to get the side of the triangle. Find the area of the triangle. Find the area of sector. Subtract triangle from sector.
in that sector question what was the area supposed to be ? for the shaded part or for the whole shape
Reply 34
Avatar for Fadel
Fadel
16
Original post by ToxicPhantom007
in that sector question what was the area supposed to be ? for the shaded part or for the whole shape


Shaded
Original post by Fadel
Shaded


huh thank god
one of friends calc for the whole shape and it confused me a bit
Reply 36
Avatar for EUSHA
EUSHA
2
im 100% sure it was 27/64 in the last one.
it was area under line- area under curve.
calculation was like this:integ(limit 2 to .5)[-.25x+.5]-integ(limit 2 to .5)[x^3-3x^2+2x]
Reply 37
Avatar for t
t
13
Original post by EUSHA
im 100% sure it was 27/64 in the last one.
it was area under line- area under curve.
calculation was like this:integ(limit 2 to .5)[-.25x+.5]-integ(limit 2 to .5)[x^3-3x^2+2x]


Are you sure it is 100%? Because I got that answer too and I'm getting freaked out if I got that wrong too in addition to all the other silly mistakes I've done. :frown:
Reply 38
Avatar for EUSHA
EUSHA
2
Original post by I <3 WORK
Are you sure it is 100%? Because I got that answer too and I'm getting freaked out if I got that wrong too in addition to all the other silly mistakes I've done. :frown:


um pretty sure
btw what was your values of angles where sin_theta was (1/3) and (-1/2)?
Original post by EUSHA
um pretty sure
btw what was your values of angles where sin_theta was (1/3) and (-1/2)?


I got 30 and -19.5 I think

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