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# M3

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1. https://8a40d6c38bafca75cc407741c0f3...%20Edexcel.pdf

question 5 b

I don't understand what they did in the mark scheme. I get that they resolve forces and thats fine, but they take moments about the point of contact, i dont get how 2rsina = w(9r/4sina-rcosa)
2. (Original post by beta_tester)
https://8a40d6c38bafca75cc407741c0f3...%20Edexcel.pdf

question 5 b

I don't understand what they did in the mark scheme. I get that they resolve forces and thats fine, but they take moments about the point of contact, i dont get how 2rsina = w(9r/4sina-rcosa)
I presume the lefthand side is OK - though it's missing a P.

For the right, you want the perpendicular distance of the line of action of the centre of mass. Refering to the diagram, this is BC.

BC = AC - AB
= 9r/4 sin a - r cos a

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