I agree it was a lot easier than the 2015 paper.(Original post by smitherito)
Core 1 was much easier than previous papers
You are Here:
Home
> Forums
>< Study Help
>< Maths, science and technology academic help
>< Maths
>< Maths Exams

AQA C1 Unofficial Markscheme
Announcements  Posted on  

Would YOU be put off a uni with a high crime rate? First 50 to have their say get a £5 Amazon voucher!  27102016 

 Follow
 41
 18052016 13:35

 Follow
 42
 18052016 13:37
(Original post by rndmtngr99)
And I got root 55 for the circle question?!? 
 Follow
 43
 18052016 13:42
Quick question, you know question 1. Did it give us the equation of AB or did we have to create it with the c=7. Or was the y=mx+7 there to confuse us??

 Follow
 44
 18052016 13:42
I thought the equation for the tangent at P is y=40x56..... since Y24=40(x2), how did you guys get gradient as 32...?

 Follow
 45
 18052016 13:43
(Original post by BlackthornRose)
Here are my answers to the questions I can remember:
Surd question: 7532 square root 5
Circle question: equation tangent I got 7x4y+8=0
Equation circle (x5)^2 + (y+3)^2 = 65 (I think I forgot to add on the additional numbers from completing the square and so got this wrong, please let me know)
Coordinates B I got (12, 7)
Length CT I got 9.
Integration question: equation of tangent I got y=32x40
x coordinate of Q I got 5/4
Area under curve
I think I correctly got the area under the curve which was 20.25 but after that I just messed up, how many marks do you think I lost for the question? I didn't recognise the whole area of triangle and minus that from the area under the curve.
Completing the square I got (x7/2)^2  41/4
There was a transformation question too and I got a translation of 0.5 and 41/4, but looking back I'm not sure if I got the signs right, I think the y value was supposed to be positive in the translation? I'm sure I got that wrong.
Something about values for k I got k=4 and k=20.
Then something else about values for k I think it was (or was it x?) And I got k>6 and k<3/2.
Another one about finding roots of an equation and I got x= 1+/ square root of 5.
Remainder theorem I got 20.
The linear factors I got (x+3)(x4)^2 (can't remember if the first factor was plus or minus actually, just used the one they gave)
That's all I can remember at the moment; if anyone else can shed some light on the ones I'm not sure about and tell me roughly how many marks they think I lost?
Also, what do you suppose the grade boundaries are this year?
No, that's the right circle equation. The area under the curve was 20.25, subtract 9 (area of triangle) to get 11.25. The translation seems right. (x+3)(x4)^2 was right, but I expect the mark scheme will require (x+3)(x4)(x4)  as it wanted 3 linear factors.Marks lost is hard to say tbh.Post rating:1 
 Follow
 46
 18052016 13:43
(Original post by TheOtherSide.)
You're back!Post rating:1 
 Follow
 47
 18052016 13:45
(Original post by musslih)
I thought the equation for the tangent at P is y=40x56..... since Y24=40(x2), how did you guys get gradient as 32...? 
 Follow
 48
 18052016 13:50
(Original post by timtjtim)
No, that's the right circle equation. The area under the curve was 20.25, subtract 9 (area of triangle) to get 11.25. The translation seems right. (x+3)(x4)^2 was right, but I expect the mark scheme will require (x+3)(x4)(x4)  as it wanted 3 linear factors.Marks lost is hard to say tbh.
What do you suppose the grade boundaries will be like? 
 Follow
 49
 18052016 13:50
(Original post by BlackthornRose)
Here are my answers to the questions I can remember:
Surd question: 7532 square root 5
Circle question: equation tangent I got 7x4y+8=0
Equation circle (x5)^2 + (y+3)^2 = 65 (I think I forgot to add on the additional numbers from completing the square and so got this wrong, please let me know)
Coordinates B I got (12, 7)
Length CT I got 9.
Integration question: equation of tangent I got y=32x40
x coordinate of Q I got 5/4
Area under curve
I think I correctly got the area under the curve which was 20.25 but after that I just messed up, how many marks do you think I lost for the question? I didn't recognize the whole area of triangle and minus that from area under curve thing.
Completing the square I got (x7/2)^2  41/4
There was a transformation question too and I got a translation of 0.5 and 41/4, but looking back I'm not sure if I got the signs right, I think the y value was supposed to be positive in the translation? I'm sure I got that wrong.
Something about values for k I got k=4 and k=20.
Then something else about values for k I think it was (or was it x?) And I got k>6 and k<3/2.
Another one about finding roots of an equation and I got x= 1+/ square root of 5.
Remainder theorem I got 20.
The linear factors I got (x+3)(x4)^2 (can't remember if the first factor was plus or minus actually, just used the one they gave)
That's all I can remember at the moment, if anyone else can shed some light on the ones I'm not sure about and tell me roughly how many marks they think I lost?
Also, what do you suppose the grade boundaries are this year?
Edit: I actually just realised that I'm pretty sure my equation for the circle is right, as the equation is (xa)^2 + (yb)^2=r^2 and i worked out the radius using coordinates for centre and point A then just plugged it into equation.
Also, there was another question that asked for the value of k at a specific point like (3+5k, 43k) to the best of my memory, and I got k=30.
Anyone else?Last edited by Agent R5; 18052016 at 13:52. Reason: also what question was this 'And I got k>6 and k<3/2' on? 
 Follow
 50
 18052016 13:52
How did people get root 65 for the radius of the circle when the centre coordinates were (5,3). On expanding this came out as root 34 surely?
Post rating:2 
 Follow
 51
 18052016 13:53
(Original post by AyyS)
Quick question, you know question 1. Did it give us the equation of AB or did we have to create it with the c=7. Or was the y=mx+7 there to confuse us?? 
 Follow
 52
 18052016 13:57
(Original post by BlackthornRose)
Here are my answers to the questions I can remember:
Surd question: 7532 square root 5
Circle question: equation tangent I got 7x4y+8=0
Equation circle (x5)^2 + (y+3)^2 = 65 (I think I forgot to add on the additional numbers from completing the square and so got this wrong, please let me know)
Coordinates B I got (12, 7)
Length CT I got 9.
Integration question: equation of tangent I got y=32x40
x coordinate of Q I got 5/4
Area under curve
I think I correctly got the area under the curve which was 20.25 but after that I just messed up, how many marks do you think I lost for the question? I didn't recognize the whole area of triangle and minus that from area under curve thing.
Completing the square I got (x7/2)^2  41/4
There was a transformation question too and I got a translation of 0.5 and 41/4, but looking back I'm not sure if I got the signs right, I think the y value was supposed to be positive in the translation? I'm sure I got that wrong.
Something about values for k I got k=4 and k=20.
Then something else about values for k I think it was (or was it x?) And I got k>6 and k<3/2.
Another one about finding roots of an equation and I got x= 1+/ square root of 5.
Remainder theorem I got 20.
The linear factors I got (x+3)(x4)^2 (can't remember if the first factor was plus or minus actually, just used the one they gave)
That's all I can remember at the moment, if anyone else can shed some light on the ones I'm not sure about and tell me roughly how many marks they think I lost?
Also, what do you suppose the grade boundaries are this year?
Edit: I actually just realised that I'm pretty sure my equation for the circle is right, as the equation is (xa)^2 + (yb)^2=r^2 and i worked out the radius using coordinates for centre and point A then just plugged it into equation.
Also, there was another question that asked for the value of k at a specific point like (3+5k, 43k) to the best of my memory, and I got k=30.
Anyone else?Post rating:1 
 Follow
 53
 18052016 13:58
Was the values for k > (3/2<k<6 ) or (3/2>k or k>6)
*Brackets show the 2 different answers* 
 Follow
 54
 18052016 13:58
(Original post by BearackObama)
How did people get root 65 for the radius of the circle when the centre coordinates were (5,3). On expanding this came out as root 34 surely?
Now plug a,b into (xa)^2 + (yb)^2 = r^2
We get (x5)^2 + (y+3)^2 = r^2.
Now for r  we know that A lies on this circle and is at coordinates A(2,1). That gives a triangle, with sides 4 and 7. 7^2 + 4^2 = 65, so r = √65. But we want r^2, and √65^2 = 65 so k = 65.
My image may help  see attached.Post rating:3 
 Follow
 55
 18052016 13:58
(Original post by BearackObama)
How did people get root 65 for the radius of the circle when the centre coordinates were (5,3). On expanding this came out as root 34 surely?
(x5)^2 + (y+3)^2 = k
sub A into it
(25)^2 + (1+3)^2 = k
(7)^2 + (4)^2 = k
49 + 16 = k
k = 65Post rating:1 
 Follow
 56
 18052016 13:59
(Original post by BlackthornRose)
Here are my answers to the questions I can remember:
Surd question: 7532 square root 5
Circle question: equation tangent I got 7x4y+8=0
Equation circle (x5)^2 + (y+3)^2 = 65 (I think I forgot to add on the additional numbers from completing the square and so got this wrong, please let me know)
Coordinates B I got (12, 7)
Length CT I got 9.
Integration question: equation of tangent I got y=32x40
x coordinate of Q I got 5/4
Area under curve
I think I correctly got the area under the curve which was 20.25 but after that I just messed up, how many marks do you think I lost for the question? I didn't recognize the whole area of triangle and minus that from area under curve thing.
Completing the square I got (x7/2)^2  41/4
There was a transformation question too and I got a translation of 0.5 and 41/4, but looking back I'm not sure if I got the signs right, I think the y value was supposed to be positive in the translation? I'm sure I got that wrong.
Something about values for k I got k=4 and k=20.
Then something else about values for k I think it was (or was it x?) And I got k>6 and k<3/2.
Another one about finding roots of an equation and I got x= 1+/ square root of 5.
Remainder theorem I got 20.
The linear factors I got (x+3)(x4)^2 (can't remember if the first factor was plus or minus actually, just used the one they gave)
That's all I can remember at the moment, if anyone else can shed some light on the ones I'm not sure about and tell me roughly how many marks they think I lost?
Also, what do you suppose the grade boundaries are this year?
Edit: I actually just realised that I'm pretty sure my equation for the circle is right, as the equation is (xa)^2 + (yb)^2=r^2 and i worked out the radius using coordinates for centre and point A then just plugged it into equation.
Also, there was another question that asked for the value of k at a specific point like (3+5k, 43k) to the best of my memory, and I got k=30.
Anyone else?
what question was this ?Post rating:1 
 Follow
 57
 18052016 13:59
(Original post by Agent R5)
what about the question where you had to sketch the 2x"2 graph or something and state the yintercept, any1 know how many marks that was? 2 or 3?Post rating:1 
 Follow
 58
 18052016 14:01
(Original post by vyyzx)
Was the values for k > (3/2<k<6 ) or (3/2>k or k>6)
*Brackets show the 2 different answers* 
 Follow
 59
 18052016 14:02
to work out radius of circle u needed to find the "difference" in x and y directions and use Pythagoras to find the actual length of it
if you do M1 you would be very familiar with this.
think of it like this, how do you get from co ordinates (10,10) to (5,6)
well you go 5 in x direction and 4 in y direction
now think of x and y as being horizontal and vertical respectively.
what is the hypotenuse of that triangle u have? ( hypotenuse = radius of the circle) 
 Follow
 60
 18052016 14:03
(Original post by Agent R5)
Then something else about values for k I think it was (or was it x?) And I got k>6 and k<3/2.
what question was this ?
Write a reply…
Reply
Submit reply
Register
Thanks for posting! You just need to create an account in order to submit the post Already a member? Sign in
Oops, something wasn't right
please check the following:
Sign in
Not got an account? Sign up now
Updated: May 24, 2016
Share this discussion:
Tweet
TSR Support Team
We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.