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# Edexcel AS Mathematics C2- 25th May 2016 Thread

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1. (Original post by discuss)
how did people find the upper bound needed to find the area of s ?
The curve touched the X axis at two points. One of them was 0 and the other one, to find out what it was you needed to sub in y = 0 into the equation which would give you a value for x

(Original post by Darkseid1234)
Did anyone else get P is 66? How are people getting 120?
When you differentiated the equation, and made it equal to 0, you get an answer of X = 16.63. If you sub that value of X back into the equation for P, you get an answer of P = 120
2. (Original post by Bhaiyattt)
The curve touched the X axis at two points. One of them was 0 and the other one, to find out what it was you needed to sub in y = 0 into the equation which would give you a value for x

When you differentiated the equation, and made it equal to 0, you get an answer of X = 16.63. If you sub that value of X back into the equation for P, you get an answer of P = 120
I defo did that and got 66 and people I spoke to got similar answers as well.
I can't remember the exact equation for P feel free to remind me but i'm sure it was 66
3. Actually the equation for P was 1000/X+X/12(4pi+36-3root3)
4. (Original post by Bhaiyattt)
The curve touched the X axis at two points. One of them was 0 and the other one, to find out what it was you needed to sub in y = 0 into the equation which would give you a value for x

When you differentiated the equation, and made it equal to 0, you get an answer of X = 16.63. If you sub that value of X back into the equation for P, you get an answer of P = 120
I substituted X into a formula do you reckon i'll get a method for substituting even though it may have been the wrong formula?
5. Does anyone remember the upper bound X coordinate for the 7b integration question?
6. (Original post by 10moorej)
Does anyone remember the upper bound X coordinate for the 7b integration question?
I think it was 9, I think the answer was 243/10 or 24.3
7. Solutions:
Attached Images
8. C2 S16 Solution (L) (1).pdf (89.9 KB, 449 views)
9. Hi I think there's a mistake in this on question 1c... The difference is definitely not 256 haha. It looks like just an oversight, accidentally putting the answer from 1B there
Hi I think there's a mistake in this on question 1c... The difference is definitely not 256 haha. It looks like just an oversight, accidentally putting the answer from 1B there
Yh I didn't make it but I realised. I think it should be 1.602?
11. Yeah I just checked it and that's right (hopefully)
12. for the log question, how many marks out of 4 would i get if make y=2x and gettting 1.38 as the final answer.
y^7=7y
y^6=7
y=1.38
13. (Original post by JAFF2400)
This video really sums up the C2 exam...

That was absolutely hilarious!!
Here's my unofficial mark scheme, with the actual questions.
Wow, fantastic! Thanks so much
15. 1 I mean

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16. That markscheme has actually given me confidence.
17. (Original post by DW4)
That was absolutely hilarious!!
Thank you so much means a lot! I'm glad you liked it
18. (Original post by Darkseid1234)
Did anyone else get P is 66? How are people getting 120?
(Original post by discuss)
how did people find the upper bound needed to find the area of s ?
(Original post by 10moorej)
Does anyone remember the upper bound X coordinate for the 7b integration question?
Model solutions here.
19. (Original post by JAFF2400)
Thank you so much means a lot! I'm glad you liked it
how the hell was 9 the upper limit . i substituted 0 into the equation and got 4 ?
20. (Original post by Bhaiyattt)
The curve touched the X axis at two points. One of them was 0 and the other one, to find out what it was you needed to sub in y = 0 into the equation which would give you a value for x

When you differentiated the equation, and made it equal to 0, you get an answer of X = 16.63. If you sub that value of X back into the equation for P, you get an answer of P = 120
u don't have to make y=0 bec they already give you the x-axis which is 0,4

and event if you make y=0 the answer will be the same 4 by using the log concept

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