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# Fp1 matrices

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1. What am I doing wrong? I havent finished yet but do far it looks nothing like the ms
Q10ii.
http://m.imgur.com/G5pn2lC,BQWZ8HU,wEccZsU
2. (Original post by Super199)
What am I doing wrong? I havent finished yet but do far it looks nothing like the ms
Q10ii.
http://m.imgur.com/G5pn2lC,BQWZ8HU,wEccZsU
Look up finding the matrix of minors again, you shouldn't be inlcuding the coefficients of when computing the minor determinants (or whatever it's called).

So, like where you did 0(6a - 3) it should be just 6a - 3. Not including the coefficient thingy.
3. (Original post by Zacken)
Look up finding the matrix of minors again, you shouldn't be inlcuding the coefficients of when computing the minor determinants (or whatever it's called).

So, like where you did 0(6a - 3) it should be just 6a - 3. Not including the coefficient thingy.
Yh got it cheers. How do I work out 10iii?
(AB)^-1= B^-1A^-1.
Idk what to do after.
4. (Original post by Super199)
Yh got it cheers. How do I work out 10iii?
(AB)^-1= B^-1A^-1.
Idk what to do after.
Yeah, so B^(-1) = (AB)^(-1) * A by multiply both sides by A. And you know (AB)^(-1).
5. (Original post by Zacken)
Yeah, so B^(-1) = (AB)^(-1) * A by multiply both sides by A. And you know (AB)^(-1).
Is A^-1A = I

or AA^-1= I?
6. (Original post by Super199)
Is A^-1A = I

or AA^-1= I?
Both.
7. (Original post by Zacken)
Both.
is I = 1 0
0 1

or does it have a value of 1?
8. (Original post by Super199)
is I = 1 0
0 1
Correct.
9. (Original post by Zacken)
Correct.
http://www.ocr.org.uk/Images/63184-q...hematics-1.pdf

q5. What does it mean by using the determinant of an appropriate matrix?
No worries I think I got it actually
10. (Original post by Super199)
http://www.ocr.org.uk/Images/63184-q...hematics-1.pdf

q5. What does it mean by using the determinant of an appropriate matrix?
No worries I think I got it actually
11. (Original post by Zacken)
http://m.imgur.com/zHrzLmt,nxdr3vb

Q7ii. I dont think ive done the proof right
12. (Original post by Super199)
http://m.imgur.com/zHrzLmt,nxdr3vb

Q7ii. I dont think ive done the proof right
Looks fine although you'd want to say -uk not +uk .
13. (Original post by Zacken)
Looks fine although you'd want to say -uk not +uk .
Yup my bad. Same paper 8iii.

Can I let x= alpha +1

So alpha= x-1 and then sub it in? or do I have to use the previous part some how?
14. (Original post by Super199)
Yup my bad. Same paper 8iii.

Can I let x= alpha +1

So alpha= x-1 and then sub it in? or do I have to use the previous part some how?
Can't see the question.
15. (Original post by Super199)
Yup my bad. Same paper 8iii.

Can I let x= alpha +1

So alpha= x-1 and then sub it in? or do I have to use the previous part some how?
As the question says, hence assume you should just continue.
16. (Original post by Zacken)
Can't see the question.
http://www.ocr.org.uk/Images/63184-q...hematics-1.pdf
17. (Original post by Nish123)
As the question says, hence assume you should just continue.
I don't see how though.
18. (Original post by Super199)
I don't see how though.
A quadratic equations with those roots are:

19. (Original post by Nish123)
As the question says, hence assume you should just continue.
Plus, the same thing is not happening to each root (symmetry) , so I am assuming that you cannot do the "slick method" ie substitution without making it longer.
20. (Original post by Super199)
I don't see how though.
Sorry, I have just joined Student Room so don't know how to use Latex however just sum the new roots and multiply them together, ie (a+1)(b-1) and (a+1)+(b-1) and then manipulate until you have that in terms of alpha and beta. I have used a instead of alpha and b instead of beta.

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