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# How did you find the Edexcel FP1?

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• View Poll Results: How was the FP1 for you?
very hard
148
23.95%
hard
186
30.10%
ok
167
27.02%
easy
70
11.33%
very easy
47
7.61%

1. (Original post by 13 1 20 8 42)
I am intrigued to see this paper now..
It wasn't anything strange - I think finding the midpoint of a line threw people off and some weird awkward wording that's all.
2. Interested in seeing the paper too - I'd be happy to try and provide a correction
3. (Original post by oShahpo)
I got -2.03 for the angle.
Not negative as P was in top left quadrant.
4. (Original post by JamieOH)
Not negative as P was in top left quadrant.
Oh yea you're right, I took the angle I got away from pi. There was another negative angle though, right?
5. (Original post by oShahpo)
14/5 root2 or something similar.
15root2/4
6. Havent seen the paper yet, though the initial reaction doesn't help my nerves for FP2 and FP3
7. (Original post by JamieOH)
Perpendicular I put? If R was 5? Maybe it wasnt
(Original post by oShahpo)
I didn't say the gradient was the same, I proved it they were parallel however using the ideas of vectors, that is that OA = 2 * PR, would I lose a mark for that?
The two lines were parallel from what I got, both had a gradient of -2.
JamieOH I don't think they were perpendicular as they weren't at right angles

oShahpo I don't know, I might have lost a mark for not mentioning the length/vectors or you might have lost a mark for not mentioning the gradient.... who knows
8. (Original post by themechguy)
The two lines were parallel from what I got, both had a gradient of -2.
JamieOH I don't think they were perpendicular as they weren't at right angles

oShahpo I don't know, I might have lost a mark for not mentioning the length/vectors or you might have lost a mark for not mentioning the gradient.... who knows
I did mention they have the same length, arghh I would be angry if I lost a mark for not mentioning the gradient.
9. That paper was horrible! I'd been working so hard to get an A (I much prefer the applied stuff) and was managing to do it ok. I couldn't get the answer to the parabola part 1, I got the y(p+q) =2x (or something like that) but not the last bit.
Also I only got the 1st proof by subtracting k+1 not adding it.

WHAT HAPPENED??????
10. (Original post by oShahpo)
I did mention they have the same length, arghh I would be angry if I lost a mark for not mentioning the gradient.
I think it was like 1 mark, so I literally just stated parallel, it was fairly obvious from the diagram. Not sure they asked for a formal proof.
11. (Original post by edothero)
Havent seen the paper yet, though the initial reaction doesn't help my nerves for FP2 and FP3
Wasn't really hard at all, nothing mentally challenging. Some questions might have been poorly worded and some questions were lengthy, but that's all.
12. (Original post by Armpits)
I think it was like 1 mark, so I literally just stated parallel, it was fairly obvious from the diagram. Not sure they asked for a formal proof.
It was definitely 2 marks.
13. (Original post by themechguy)
For the relationship between the two chords I said they were parallel as the gradient was the same.
I wrote that the length of one was double the other
14. (Original post by themechguy)
For the relationship between the two chords I said they were parallel as the gradient was the same.
haha yeah, I only realised that the imaginary part = 0 in a real number with about 5 minutes to go, i think i had 20 seconds left when i got onto part e, how many marks was that question? 1 or 2?
15. (Original post by oShahpo)
I got -2.03 for the angle.
I don't remember entirely but I think x was negative and y was positive, giving +2.03.
16. (Original post by Unravelling)
I don't remember entirely but I think x was negative and y was positive, giving +2.03.
Yea it definitely is +2.03, I took the angle I got away from pi. There must have been another negative angle though, right?
17. (Original post by oShahpo)
I didn't say the gradient was the same, I proved it they were parallel however using the ideas of vectors, that is that OA = 2 * PR, would I lose a mark for that?
I anticipate:

B1 parallel
B1 gradient -2/same length shown or stated

I said parallel, gradient -2, both making an angle of 26 or so degrees with the horizontal

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18. (Original post by Armpits)
15root2/4
Yea, I have the memory of a gerbil.
19. Wonder how I got they were perpendiuclar... Was it QR and OP right? I had R as 5?
20. It was 2.03 because the complex number was -1+2i , therefore you do pi - tan-1(2/1) = 2.03....

You might have put -1 into the tan part which could screw things up, but because the argument was clearly less than or equal to pi and greater than 0, you know it must be a positive answer for the argument. Either way, if you put -2.03 I'm sure that's only 1 mark deducted as you performed the calculations correctly

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