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1. Would I get a mark for calculating the midpoint for the last one, and putting the y bit equal to 0 and getting p?
2. I didnt see the simplification for finding the x value in 9)b) and just made my equation equal to the value given. I then used the x value given to find the y value. Would this still give me a mark?
3. (Original post by Arsey)
Here are my solutions to the FP1 paper.

Reasonable paper I thought, a few tricky bits
how do I know your solutions are correct?
4. (Original post by mathsisjust)
how do I know your solutions are correct?
It is fairly easy for someone with experience to be sure of 100% or near 100% accuracy on papers of this level...also if something were incorrect someone would have noticed by now
5. (Original post by 13 1 20 8 42)
It is fairly easy for someone with experience to be sure of 100% or near 100% accuracy on papers of this level...also if something were incorrect someone would have noticed by now
I didn't know he was experienced
6. (Original post by Arsey)
Here are my solutions to the FP1 paper.

Reasonable paper I thought, a few tricky bits
IAL FP1 solutions here

http://www.thestudentroom.co.uk/show...3#post65033993
7. (Original post by Arsey)
Here are my solutions to the FP1 paper.

Reasonable paper I thought, a few tricky bits
would you be able to predict grade boundaries for this paper?
8. (Original post by mathsisjust)
Is Arsey a math's teacher??
Arsy Is a very smart mathematician and therefore has a very high probability of getting all the answer correct. I tested this with a 1% Hypothesis testing.
9. (Original post by mathsnerd27)
would you be able to predict grade boundaries for this paper?
My Predictions:

74- 100 UMS
68 - 90 UMS (A* equiv)
60 - 80 Ums (A)
54 - 70 UMS (B)
10. (Original post by NoahMal)
My Predictions:

74- 100 UMS
68 - 90 UMS (A* equiv)
60 - 80 Ums (A)
54 - 70 UMS (B)
nah

100 UMS - 75
90 UMS - 70
80 UMS - 62
70 UMS - 56
11. (Original post by marinara pizza)
nah

100 UMS - 75
90 UMS - 70
80 UMS - 62
70 UMS - 56
The 90 UMS boundary must be equidistant from the 80 and 100 UMS boundaries
12. (Original post by NoahMal)
Arsy Is a very smart mathematician and therefore has a very high probability of getting all the answer correct. I tested this with a 1% Hypothesis testing.
lool
13. (Original post by olmomiau)
The 90 UMS boundary must be equidistant from the 80 and 100 UMS boundaries
if you insist:

100 UMS = 75
90 UMS = 70
80 UMS = 65
14. (Original post by NoahMal)
My Predictions:

74- 100 UMS
68 - 90 UMS (A* equiv)
60 - 80 Ums (A)
54 - 70 UMS (B)
I second this
15. do u need to put sqrt 5 in 3 sf to get the one mark?????
16. I have posted solutions to the F1 paper, I thought it was a fair bit easier than UK FP1
17. (Original post by mathsisjust)
how do I know your solutions are correct?
I am Arsey
18. (Original post by mathsnerd27)
would you be able to predict grade boundaries for this paper?
75 = 100ums
69 = 91ums
68 = 89ums
62 for 80ums
54 for 70ums

would be my guess
19. (Original post by Arsey)
75 = 100ums
69 = 91ums
68 = 89ums
62 for 80ums
54 for 70ums

would be my guess
For the first Proof question. I did the n=1 step and I worked out what need to be added (2k+3/(k+1)^2(k+2)^2 but I couldnt simplify it to the actual answer. How many marks would that be?
20. (Original post by 4nonymous)
For the first Proof question. I did the n=1 step and I worked out what need to be added (2k+3/(k+1)^2(k+2)^2 but I couldnt simplify it to the actual answer. How many marks would that be?
Usually 1 mark for proving true for n=1, 1 mark for assuming n=k. Sometimes they give a mark for an attempt to prove, sometimes they only give 3rd mark for successful n=k+1 proof. Other 2 marks are available for successful proof for n=k+1 AND conclusion, you will (most definitely) not get conclusion marks without proving for n=k+1.

I'd say you probably have 2 or 3 marks out of 5.

Updated: May 23, 2016
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