Original post by Ravster
Part C:
the coordinates of N are (0,-168)
to find the area I integrated between x=0 and 4 and that's as far as I got.
In the mark scheme they have found the area of the rectangle and subtracted the area between 0 and 4.
Can someone explain what I'm missing here ?
Part C:
the coordinates of N are (0,-168)
to find the area I integrated between x=0 and 4 and that's as far as I got.
In the mark scheme they have found the area of the rectangle and subtracted the area between 0 and 4.
Can someone explain what I'm missing here ?
you answered your own question
but you need to find the area of the rectangle from O to N to P to 4
integrate to find area under the curve between 0 and 4 like you said then minus area of rectangle by area under the curve
(edited 7 years ago)
Original post by thefatone
you answered your own question
but you need to find the area of the triangle from O to N to P to 4
integrate to find area under the curve between 0 and 4 like you said then minus area of triangle by area under the curve
but you need to find the area of the triangle from O to N to P to 4
integrate to find area under the curve between 0 and 4 like you said then minus area of triangle by area under the curve
A triangle has straight lines. This isn't a straight line. Hence it's not a triangle.
Original post by Zacken
A triangle has straight lines. This isn't a straight line. Hence it's not a triangle.
good point i'll change it to rectangle
Original post by thefatone
you answered your own question
but you need to find the area of the rectangle from O to N to P to 4
integrate to find area under the curve between 0 and 4 like you said then minus area of rectangle by area under the curve
but you need to find the area of the rectangle from O to N to P to 4
integrate to find area under the curve between 0 and 4 like you said then minus area of rectangle by area under the curve
That's what I don't understand.
By integrating between 0 and 4 aren't we then left with the area of the shaded region?
Why do we need to involve the rectangle?
Original post by Ravster
That's what I don't understand.
By integrating between 0 and 4 aren't we then left with the area of the shaded region?
Why do we need to involve the rectangle?
By integrating between 0 and 4 aren't we then left with the area of the shaded region?
Why do we need to involve the rectangle?
No that's the bit you missed, By integrating between 0 and 4 you get the area between the curve and x-axis
involving the rectangle which includes all of the shaded area and the area between the curve and x-axis is what you need
Original post by Ravster
That's what I don't understand.
By integrating between 0 and 4 aren't we then left with the area of the shaded region?
Why do we need to involve the rectangle?
By integrating between 0 and 4 aren't we then left with the area of the shaded region?
Why do we need to involve the rectangle?
Nopes... the area that you find via integration is the blue area below.
Quick Reply
Related discussions
- Mechanics help
- essay question
- Help integration
- Help with differential equations please.
- Help maths urgent ‼️
- Help urgent maths
- Applied Calculus Help
- Help I don’t understand integration
- A level maths mechanics question (1)
- integration
- Does anyone know a sheet with all the differentiated and integrated functions?
- Maths: Integration
- A Level maths mechanics help
- A-level Maths, Integration, Finding area between curves & Lines.
- Postgraduate Master's Loan - 2
- Further maths integration help
- Integration question
- Can I get student finance for my 4th year on my MSci course?
- Integrated masters
- Numerical solution
Latest
Trending
Last reply 2 days ago
Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrongMaths
71
Trending
Last reply 2 days ago
Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrongMaths
71
