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1. Under what conditions when solving an inequality that involves logs does the more than or equal sign swap round?
2. (Original post by Mackiemcmasher)
Under what conditions when solving an inequality that involves logs does the more than or equal sign swap round?
The inequality sign swaps round in you divide by a negative number.
The log of any number < 0 will be negative

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3. (Original post by gdunne42)
The inequality sign swaps round in you divide by a negative number.
The log of any number < 0 will be negative

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Ah ok thank you.
4. You could also think about why it works.

Eg if you have 8>6 then you know that -1 * 8 < -1* 6, which is the same as -8 < -6, so you see that the sign gets flipped around when it's multiplied by a negative number. (And logx is negative for any x less than 1, and log1=0.)

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