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# maths question on functions

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1. So the question is f(x) = 4/3+x

g(x) = 9 - 2x^2

So when i put F into g i get

4/9-2x^2 + 3 but, i need to get the plus 3 a common demonitor so i multipy it by 9 - 2x^2, but the answer is completley different to what i get where am i going wrong?
2. (Original post by SunDun111)
So the question is f(x) = 4/3+x

g(x) = 9 - 2x^2

So when i put F into g i get

4/9-2x^2 + 3 but, i need to get the plus 3 a common demonitor so i multipy it by 9 - 2x^2, but the answer is completley different to what i get where am i going wrong?
Don't understand, you're being totally ambiguous. Put up a picture.
3. (Original post by Zacken)
Don't understand, you're being totally ambiguous. Put up a picture.
Ok basically, the question is f(x) = 4 / 3 + x

g(x) = 9 - 2x^2

The answer is 2 / 6 - x^2

I just want to know how and why that is the answer, If u dont understand ill get a picture?
4. (Original post by SunDun111)
Ok basically, the question is f(x) = 4 / 3 + x

g(x) = 9 - 2x^2

The answer is 2 / 6 - x^2

I just want to know how and why that is the answer, If u dont understand ill get a picture?
means replacing every time you see an x in 4/(3 + x) (please use brackets) you replace x with g(x).

So

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