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# Official AQA New Spec AS Level Physics Paper 2 - 9th June

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1. (Original post by sophbunny161)
I got this, but am probs wrong
2. What did everyone put for why the meter wasnt suitable
3. (Original post by 11234)
What did everyone put for why the meter wasnt suitable
I got that each division would be worth 2000 μV so all of the values would lie between 0 and the first small line, so you could not take accurate enough readings... But it don't know if thats right.
4. seeing as no one got the same I'm guessing it was wrong, but for the zero error one I got 0.37 as it was minus 0.07😭 can someone explain it to me please
5. (Original post by rs98)
I got that each division would be worth 2000 μV so all of the values would lie between 0 and the first small line, so you could not take accurate enough readings... But it don't know if thats right.
I said something along those lines and how range is not enough meaning you cant get a precise and accurate measurement but i forgot to mention 2000
6. (Original post by bowliez)
seeing as no one got the same I'm guessing it was wrong, but for the zero error one I got 0.37 as it was minus 0.07😭 can someone explain it to me please
If you've got a scale and it when it's closed it reads -0.07, and then when you are taking a reading it is 0.44, then the reading is how far it's moved, i.e. 0.44 - - 0.07 = 0.44 + 0.07 = 0.51mm
7. (Original post by 11234)
I said something along those lines and how range is not enough meaning you cant get a precise and accurate measurement but i forgot to mention 2000
I don't know if you would have to mention it for the marks, but I just thought since we had just worked out the maximum value, and it said how many divisions there were, I would include it just in case.
8. How do linear exams work do we get ums?
9. (Original post by KilliKonKarnage)
Yo, you worked out hours, when Power is energy transferred per second. So I did divided by (365x24x60x60) but I'm not sure now. Is energy also written as kWh?

Does kWh=J or does it =kJ
I though you have to find it per second , it says kWh so 1000 x 10^3 W divided by 3600
And i got 277
10. (Original post by rs98)
If you've got a scale and it when it's closed it reads -0.07, and then when you are taking a reading it is 0.44, then the reading is how far it's moved, i.e. 0.44 - - 0.07 = 0.44 + 0.07 = 0.51mm
how ever it could've been that when the clips were closed the student might have closed it tightly. so they said at roughly 20mm the reading was 0.2(something) so by using that it was a value of 0.4398... for the string
11. (Original post by nav5678)
how ever it could've been that when the clips were closed the student might have closed it tightly. so they said at roughly 20mm the reading was 0.2(something) so by using that it was a value of 0.4398... for the string
I think that the roughly 20mm was just to give you an example of how to read the scale. I don't think that you were supposed to use that value to calculate anything else.
12. (Original post by alhrona)
I though you have to find it per second , it says kWh so 1000 x 10^3 W divided by 3600
And i got 277
Yeah thats what I did
13. (Original post by metrize)
I wrote that assuming 365 days in a year, the number they gave us divided by (365*24) and that equals 114W
Yeah but the question gives you a value of 100kWh, h is hours I think, so to get Watts you divide by (60×60) which is 1 hour
14. Is there an unofficial mark scheme yet?
15. (Original post by rs98)
I got that each division would be worth 2000 μV so all of the values would lie between 0 and the first small line, so you could not take accurate enough readings... But it don't know if thats right.
Yes i said that. I said that cos of that the readings wont be precise enough and the range too large
16. (Original post by KilliKonKarnage)
Yo, you worked out hours, when Power is energy transferred per second. So I did divided by (365x24x60x60) but I'm not sure now. Is energy also written as kWh?

Does kWh=J or does it =kJ
It was kWh so i thought it was kW multipled by hours as the units said so i divided by hours ti just get kW on its own
17. (Original post by mstrcvk)
Yeah but the question gives you a value of 100kWh, h is hours I think, so to get Watts you divide by (60×60) which is 1 hour
It was kWh so i divided by hours to get just kW
18. Pretty sure im right, if you google kwh to kw it tells you that you divide by hours
19. So pissed off I forgot to add the ball's diameter to the measurement to it's surface in the moments question. I swear if error carried forward in this paper isn't nice I'm gonna do so bad.
20. (Original post by CBPAS)

2015 it was 97/140 for an A
2014 - 109/140
2013 - 108/140
2012 - 105/140
2011 - 101/140

so probably around 100-110 for an A but you can't really tell since its the first year
Thanks bro. That gives me much more hope tbh. Luckily I think I did enough in Paper one.

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